There are 6.022 × 10²³ atoms in 39.948 g of argon and 4.0026 g of helium.
Explanation:
39.945 g/mole is the molar mass of argon so 39.948 g of argon are equal to 1 mole of argon.
4.0026 g/mole is the molar mass of helium so 4.0026 g of helium are equal to 1 mole of helium.
We know that Avogadro's number tell us the number of particles in 1 mole of substance which is 6.022 × 10²³.
So in 39.948 g of argon and 4.0026 g of helium contains the same number of atoms, 6.022 × 10²³.
Learn more about:
Avogadro's number
brainly.com/question/14148121
brainly.com/question/1445383
brainly.com/question/1528951
#learnwithBrainly
C. chlorophyll
gc sh jj cd dhjjfddr
Answer:
D
Explanation:
Nuclear binding energy curve. During the nuclear splitting or nuclear fusion, some of the mass of the nucleus gets converted into huge amounts of energy and thus this massis removed from the total mass of the original particles, and the mass is missing in the resulting nucleus.
