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PtichkaEL [24]
4 years ago
9

A 2.0 L volume of hydrogen gas is combined with 1.0 L of oxygen gas to produce 2.0 L of water vapor. Does oxygen undergo a chemi

cal or physical change? Explain
Chemistry
1 answer:
bekas [8.4K]4 years ago
7 0

The properties like shape, structure, etc. that define the appearance of matter is said to be its physical properties whereas the properties like oxidation, toxicity, etc. that defines how a new product is formed from the other substances is said to be its chemical properties.

It is given that a 2.0 L volume of hydrogen gas is combined with 1.0 L of oxygen gas to produce 2.0 L of water vapor.  The chemical reaction is as:

H_2(g) + O_2(g) \rightarrow H_2O(g)

Since, the reaction between hydrogen and oxygen results in the formation of  complete new product, water. So, oxygen will undergo a chemical change.

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A sample of 28 Mg decays initially at a rate of 53500 disintegrations per minute, but the decay rate falls to 10980 disintegrati
prisoha [69]

Answer : The half life of 28-Mg in hours is, 6.94

Explanation :

First we have to calculate the rate constant.

Expression for rate law for first order kinetics is given by:

k=\frac{2.303}{t}\log\frac{a}{a-x}

where,

k = rate constant

t = time passed by the sample = 48.0 hr

a = initial amount of the reactant disintegrate = 53500

a - x = amount left after decay process disintegrate = 53500 - 10980 = 42520

Now put all the given values in above equation, we get

k=\frac{2.303}{48.0}\log\frac{53500}{42520}

k=9.98\times 10^{-2}hr^{-1}

Now we have to calculate the half-life.

k=\frac{0.693}{t_{1/2}}

9.98\times 10^{-2}=\frac{0.693}{t_{1/2}}

t_{1/2}=6.94hr

Therefore, the half life of 28-Mg in hours is, 6.94

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