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3 years ago

Calculate the mass in grams of 5.14×10^24 molecules of propane. The chemical formula for propane is C3H8.

Chemistry

2 answers:

elena-14-01-66 [18.8K]3 years ago

8 0

The answer is about 376.48 grams, but rounded to three significant figures, it’s 376 grams

attashe74 [19]3 years ago

7 0

the answer is 376 grams.

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Suppose that the saturation magnetization Mmax of the ferromagnetic metal nickel is 4.41 × 105 A/m. Calculate the magnetic momen

Lady bird [3.3K]

Answer : The magnetic moment of a single nickel atom is $4.82\times 10^{-24}Am^2$

Explanation :

Formula used :

$M_{max}=(\frac{N}{V})\times \mu$

where,

$M_{max}$ = saturation magnetization = $4.41\times 10^5A/m$

N = Avogadro's number = $6.022\times 10^{23}atoms/mol$

V = volume of nickel atom

$\mu$ = magnetic moment

First we have to calculate the volume of nickel atom.

$Density=\frac{Mass}{Volume}$

$8.90g/cm^3=\frac{58.71g/mol}{Volume}$

$Volume=\frac{58.71g}{8.90g/cm^3}$

$Volume=6.59cm^3=6.59\times (100)^3m^3$

Now we have to calculate the magnetic moment of a single nickel atom.

$M_{max}=(\frac{N}{V})\times \mu$

$4.41\times 10^5=(\frac{(6.022\times 10^{23})}{6.59})\times (100^3)\times \mu$

$\mu=4.82\times 10^{-24}Am^2$

Therefore, the magnetic moment of a single nickel atom is $4.82\times 10^{-24}Am^2$

7 0

3 years ago

Which of a following elements has the Smallest atomic radius 1. Ge 2. SI 3. Carbon 4. Sn

Artyom0805 [142]

Answer:

carbon

Explanation:

Atomic radius represents the distance from the nucleus to the outer shell of an element.

8 0

3 years ago

Find and fix each mistake in the following equilibrium constant expressions.

IRINA_888 [86]

Answer:

A. c. Keq=[H2]^2[S2]/[H2S]^2

B. b. Keq=[COCl2]/[CO][Cl2]

Explanation:

Hello,

In this case, considering the law of mass action which states that the equilibrium expression is written in terms of the concentration of products divided by the concentration of reactants considering the stoichiometric coefficients as powers we obtain:

A. For the reaction:

$2H_2S(g)\rightleftharpoons 2H_2(g)+S_2(g)$

The equilibrium expression is:

$Keq=\frac{[H_2]^2[S_2]}{[H_2S]^2}$

Therefore, answer is c. Keq=[H2]^2[S2]/[H2S]^2.

B. For the reaction:

$CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)$

The equilibrium expression is:

$Keq=\frac{[COCl_2]}{[CO][Cl_2]}$

Therefore, answer is b. Keq=[COCl2]/[CO][Cl2].

Regards.

8 0

3 years ago

Which one of the following pairs of acids and conjugate bases is incorrectly labeled or incorrectly matched? Acid Conjugate Base

vekshin1

Answer : The incorrect option is, (d) $NH_4^+/NH_2^-$

Explanation :

According to the Bronsted Lowry concept, Bronsted Lowry-acid is a substance that donates one or more hydrogen ion in a reaction and Bronsted Lowry-base is a substance that accepts one or more hydrogen ion in a reaction.

Or we can say that, conjugate acid is proton donor and conjugate base is proton acceptor.

(a) The equilibrium reaction will be,

$HF+H_2O\rightleftharpoons F^-+H_3O^+$

In this reaction, $HF$ is an acid that donate a proton or hydrogen to $H_2O$ base and it forms $F^-$ and $H_3O^+$ are conjugate base and acid respectively.

In this reaction, $HF/F^-$ are act as a conjugate acid-base.

(b) The equilibrium reaction will be,

$HClO+H_2O\rightleftharpoons ClO^-+H_3O^+$

In this reaction, $HClO$ is an acid that donate a proton or hydrogen to $H_2O$ base and it forms $ClO^-$ and $H_3O^+$ are conjugate base and acid respectively.

In this reaction, $HClO/ClO^-$ are act as a conjugate acid-base.

(c) The equilibrium reaction will be,

$H_2O+H_2O\rightleftharpoons OH^-+H_3O^+$

In this reaction, $H_2O$ is an acid that donate a proton or hydrogen to

In this reaction, $H_2O/OH^-$ are act as a conjugate acid-base.

(d) The equilibrium reaction will be,

$NH_4^++H_2O\rightleftharpoons NH_3+H_3O^+$

In this reaction, $NH_4^+$ is an acid that donate a proton or hydrogen to $H_2O$ base and it forms $NH_3$ and $H_3O^+$ are conjugate base and acid respectively.

In this reaction, $NH_4^+/NH_3$ are act as a conjugate acid-base.

(e) The equilibrium reaction will be,

$H_3O^++H_2O\rightleftharpoons H_2O+H_3O^+$

In this reaction, $H_3O^+$ is an acid that donate a proton or hydrogen to $H_2O$ base and it forms

In this reaction, $H_3O^+/H_2O$ are act as a conjugate acid-base.

From this we conclude that that, $NH_4^+/NH_2^-$ pairs of acids and conjugate bases is incorrectly labeled or incorrectly matched.

Hence, the incorrect option is, (d) $NH_4^+/NH_2^-$

4 0

3 years ago

Where are electrons found in the atom?

RoseWind [281]

In the electron shell

5 0

3 years ago

Calculate the mass in grams of 5.14×10^24 molecules of propane. The chemical formula for propane is C3H8.​

Calculate the mass in grams of 5.14×10^24 molecules of propane. The chemical formula for propane is C3H8.