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A spaceship on its way to another planet is traveling at a speed of 4200 miles per hour .This in units of millimeters per second will be 1877.568 m/s
Unit refers to the quantity of a constant magnitude, used to measure the magnitudes of other quantities of an identical type
1 mph = 0.44704 m/s
hence , 4200 mph = 0.44704 * 4200 = 1877.568 m/s
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Missing part of the text:
"Two masses, m1 = 2.12 kg and m2 = 9.01 kg are on a horizontal frictionless surface and they are connected together with a rope as shown in the figure."
and missing figure (see attachment)
Solution:
We can write Newton's second law for the whole system m1-m2 and for m2 only (2 equations). Only one force (F) acts on the m1-m2 system, while if we consider m2 only we have two forces acting on it: F and T (tension), in the opposite direction. So, the two equations are
where a is the acceleration of the system.
From the first equation we get
and substituting it inside the second equation, we get
re-arranging, we get
Using
,
, and using the maximum value of T that is allowed not to break the rope (T=55 N), we can find the maximum allowed value for F:
Answer: 0.471 m/s
Explanation:
We are given the followin equation:
(1)
Where:
is the Reynolds Number, which is adimensional and indicates if the flow is laminar or turbulent
When we have a laminar flow
When we have a turbulent flow
When the flow is in the transition region
is the diameter of the pipe. If the pipe ha a radius its diameter is
is the average speed of the fluid
is the density of the fluid
is the viscosity of the fluid
Isolating :
(2)
Solving for
(3)
Finally: