Which option below correctly compares the average annual dose of background radiation to the dose liked to an increased cancer r
isk?
A. The average annual dose of background radiation is 250 times larger than the dose linked to increased cancer risk.
B. The average annual dose of background radiation is 250 times smaller than the dose linked to increased cancer risk.
C. The average annual dose of background radiation is 100,000 times smaller than the dose linked to increased cancer risk.
D. The average annual dose of background radiation is 100,000 times larger than the dose linked to increased cancer risk.
A. The average annual dose of background radiation is 250 times larger than the dose linked to increased cancer risk.
B. The average annual dose of background radiation is 250 times smaller than the dose linked to increased cancer risk.
C. The average annual dose of background radiation is 100,000 times smaller than the dose linked to increased cancer risk.
D. The average annual dose of background radiation is 100,000 times larger than the dose linked to increased cancer risk.
1 answer:
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Answer:
Total contraction on the Bar = 1.22786 mm
Explanation:
Given that:
Total Length for aluminum bar = 600 mm
Diameter for aluminum bar = 40 mm
Hole diameter = 30 mm
Hole length = 100 mm
elasticity for the aluminum is 85GN/m² = 85 × 10³ N/mm²
compressive load P = 180 KN = 180 × 10³ N
Calculate the total contraction on the bar = ???
The relation used in calculating the contraction on the bar is:
The relation used in calculating the total contraction on the bar can be expressed as :
Total contraction in the Bar = (contraction in part of bar without hole + contraction in part of bar with hole)
i.e
Total contraction on the Bar =
Let's find the area of cross section without the hole and with the hole
Area of cross section without the hole is :
Using A = πd²/4
A = π (40)²/4
A = 1256.64 mm²
Area of cross section with the hole is :
A = π (40²-30²)/4
A = 549.78 mm²
Total contraction on the Bar =
Total contraction on the Bar =
Total contraction on the Bar = 2.117( 0.398 + 0.182)
Total contraction on the Bar = 2.117*(0.58)
Total contraction on the Bar = 1.22786 mm