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Lina20 [59]
3 years ago
9

What is the potential energy of a 2kg plant that is on a windowsill 1.3 m high?

Physics
1 answer:
klio [65]3 years ago
6 0

Answer:

25.48

Explanation:

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Paola conducts an investigation to determine how temperature affects plant growth. Each plant started at the same height, receiv
professor190 [17]

Answer:

HE IS WON

Explanation:

JESUS

8 0
3 years ago
A uniform beam of arbitrary, unsymmetrical cross-section and length 2???? is built-in at one end and simply supported in the ver
leonid [27]

Answer:

 the bending moment will be W from either sides

Explanation:

bending moment= force (load) * perpendicular distance, if I understand the question the distance will be 1/2 of the length

=> f x 1/2(l) =W*1/2(2) =W

5 0
3 years ago
Electric current flows through a long rod generating thermal energy at a uniform volumetric rate of
lilavasa [31]
I don't know if you need to complete this question or do it otherwise, however, I managed to find on the Internet on several places this completion of your sentence:
<span>Electric current flows through a long rod generating thermal energy at a uniform volumetric rate of q = 2 x 10</span>⁶ W/m³. 
I'm not sure whether that is the answer you were looking for, but that's what I found.
6 0
3 years ago
A 70 kg driver gets into an empty taptap to start the day's work. The springs compress 2.3×10−2 m . What is the effective spring
ANEK [815]

Answer:

29856.521 N/m

Explanation:

m=Mass\ of\ diver=70\ kg\\x=Length\ compressed\ by\ spring=2.3\times 10^{-2}\ m\\a=Acceleration\ due\ to\ gravity=9.81\ m/s^2\\F=Force\ exerted\ by\ diver=m\times a\\\Rightarrow F=70\times 9.81\\\Rightarrow F=686.7\ N\\k=spring\ constant\\F=k\times x\\\Rightarrow k=\frac {F}{x}\\\Rightarrow k=\frac {686.7}{2.3\times 10^{-2}}\\\therefore k=29856.521\ N/m

5 0
4 years ago
A disk of radius 25 cm spinning at a rate of 30 rpm slows to a stop over 3 seconds. What is the angular acceleration? B. How man
iVinArrow [24]

Answer:

Explanation:

30 rev/min (2π rad/rev) / (60 s/min) = π rad/s

α = Δω/t = (0 - π)/3 = π/3 rad/s²

θ = ½αt² = ½(π/3)3² = 1.5π radians

θ = 1.5π rad/2π rad/rev = 0.75 rev

8 0
3 years ago
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