To solve this problem we will apply the concepts related to the Magnetic Force, this is given by the product between the current, the body length, the magnetic field and the angle between the force and the magnetic field, mathematically that is,
![F = ILBsin \theta](https://tex.z-dn.net/?f=F%20%3D%20ILBsin%20%5Ctheta)
Here,
I = Current
L = Length
B = Magnetic Field
= Angle between Force and Magnetic Field
But ![\theta = 90\°](https://tex.z-dn.net/?f=%5Ctheta%20%3D%2090%5C%C2%B0)
![F = ILB](https://tex.z-dn.net/?f=F%20%3D%20ILB)
Rearranging to find the Magnetic Field,
![B = \frac{F}{IL}](https://tex.z-dn.net/?f=B%20%3D%20%5Cfrac%7BF%7D%7BIL%7D)
Here the force per unit length,
![B = \frac{1}{I}\frac{F}{L}](https://tex.z-dn.net/?f=B%20%3D%20%5Cfrac%7B1%7D%7BI%7D%5Cfrac%7BF%7D%7BL%7D)
Replacing with our values,
![B = \frac{0.130N/m}{16.5}](https://tex.z-dn.net/?f=B%20%3D%20%5Cfrac%7B0.130N%2Fm%7D%7B16.5%7D)
![B = 0.0078T](https://tex.z-dn.net/?f=B%20%3D%200.0078T)
Therefore the magnitude of the magnetic field in the region through which the current passes is 0.0078T
Answer:
Explanation:
Speed= distance/time
Or time = distance/speed
According to your question
Speed=15m/s
and. Distance=1.2km. ,we must change kilometer in meter because given speed is in m/s
D= 1.2km = 1.2×1000m =1200meter
Time = distance/ speed
1200/15 =80second
Or. 1min and 20 sec will be your answer.
Answer:
The length of the simple pendulum is 2.4 meters.
Explanation:
Time period of simple pendulum is given by :
![T=2\pi\sqrt{\dfrac{L}{g}}](https://tex.z-dn.net/?f=T%3D2%5Cpi%5Csqrt%7B%5Cdfrac%7BL%7D%7Bg%7D%7D)
L is the length of pendulum
The time period of the rope is given by :
![T=2\pi\sqrt{\dfrac{2L'}{3g}}](https://tex.z-dn.net/?f=T%3D2%5Cpi%5Csqrt%7B%5Cdfrac%7B2L%27%7D%7B3g%7D%7D)
L' is the length of the rod, L' = 3.6 m
It is given that, the rod have the same period as a simple pendulum and we need to find the length of simple pendulum i.e.
![2\pi\sqrt{\dfrac{L}{g}}=2\pi\sqrt{\dfrac{2L'}{3g}}](https://tex.z-dn.net/?f=2%5Cpi%5Csqrt%7B%5Cdfrac%7BL%7D%7Bg%7D%7D%3D2%5Cpi%5Csqrt%7B%5Cdfrac%7B2L%27%7D%7B3g%7D%7D)
On solving the above equation as :
![\dfrac{L}{g}=\dfrac{2L'}{3g}](https://tex.z-dn.net/?f=%5Cdfrac%7BL%7D%7Bg%7D%3D%5Cdfrac%7B2L%27%7D%7B3g%7D)
L = 2.4 m
So, the length of the thin rod that is hung vertically from one end and set into small amplitude oscillation 2.4 meters. Hence, this is the required solution.
Answer:
A. When two surfaces are moving relative to each other.
Explanation:
It is also know as dynamic friction
You say, "No, I will not eat your cast."