Ask question

Ask question

All categories

4 years ago

15

PLEASE HELP ME ASAP PLEASE!!!

1 answer:

Sliva [168]4 years ago

4 0

Answer:

$\large \boxed{\text{1763 psi}}$

Explanation:

We can use Dalton's Law of Partial Pressures:

Each gas in a mixture of gases equals its pressure independently of the other gases

$\begin{array}{rcl}p_{\text{NO2}} + p_{\text{CO2}} & = & p_{\text{tot}} \\p_{\text{NO2}} + \text{795 psi} & = &\text{2558 psi} \\p_{\text{NO2}} & = &\text{2558 psi - 795 psi} \\& = & \textbf{1763 psi}\\\end{array}\\\text{The partial pressure of nitrogen dioxide is $\large \boxed{\textbf{1763 psi}}$}$

You might be interested in

Draw the mechanism for the acid-catalyzed reaction of acetic acid (ethanoic acid) with the methanol to yield methyl acetate (met

timama [110]

When ethanoic acid react with methanol in the presence of H⁺ or heat it gives methyl ethanoate and water.

<h3>What is Balanced Chemical Equation ?</h3>

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

Now write the chemical equation

CH₃COOH + CH₃OH ⇄ CH₃COOCH₃ + H₂O

Here

CH₃COOH is Ethanoic acid (Acetic acid)

CH₃OH is Methanol (Methyl Alcohol)

CH₃COOCH₃ is Methyl ethanoate (Methyl Acetate)

H₂O is water

Thus from the above conclusion we can say that When ethanoic acid react with methanol in the presence of H⁺ or heat it gives methyl ethanoate and water.

Learn more about the Balanced Chemical Equation here: brainly.com/question/26694427

#SPJ4

3 0

2 years ago

Given that the specific heat of chromium is 0.455J/g∙K find the final temperature after 35.9J of energy is removed from 11.7g of

ryzh [129]

Answer:

before I tell you the answer what is your name?

Explanation:

6 0

4 years ago

A compound contains only carbon, hydrogen, and oxygen. combustion of 11.75 mg of the compound yields 17.61 mg co2 and 4.81 mg h2

Ymorist [56]

Number of moles is defined as the ratio of given mass in g to the molar mass.

First, convert the given mass of carbon dioxide in mg to g:

1 mg = 0.001 g

17.61 mg = 0.01761 g

Number of moles of carbon dioxide = $\frac{0.01761 g}{44.01 g/mol}$

= $0.0004001 mol$

Mass of carbon = number of moles of carbon dioxide \times molar mass of carbon

= $0.0004001 mol\times 12.011 g/mol$

= $0.004806 g$

Number of moles of water= $\frac{0.00481 g}{18 g/mol}$

= $2.672\times 10^{-4}$

Since, water contains two hydrogen atoms. Thus,

Moles of hydrogen = $2\times 2.672\times 10^{-4}$

= $5.34\times 10^{-4}$

Mass of hydrogen = $5.34\times 10^{-4}\times \times 1.008 g/mol$

= $5.34\times 10^{-4} g$

Mass of oxygen = $0.001175-(5.38\times 10^{-4}g+0.004806 g)$

= $0.006405 g$

Number of moles of oxygen = $\frac{0.006405 g}{15.999 g/mol}$

= $0.000400$

Now,

$C_{0.0004001} H_{0.000534} O_{0.000400}$

Divide the smallest number to get the whole number,

$C_{\frac{0.0004001}{0.000400}} H_{\frac{0.000534}{0.000400}} O_{\frac{0.000400}{0.000400}}$

we get,

$C_{1} H_{1.33} O_{1}$

Now, multiply all the subscript by 3 to get the whole number,

$C_{3} H_{4} O_{3}$ (empirical fomula)

Molar mass of the compound = $3\times 12.011 g/mol+4\times 1.008 g/mol+3\times 15.999 g/mol$

= $88.062 g/mol$

Divide given molar mass of the compound with the molar mass of the compound.

= $\frac{176.1 g/mol}{88.062 g/mol}$

= $1.999\simeq 2$

Thus, multiply the subscripts of empirical formula by 2 to get the molecular formula, we get:

$C_{6}H_{8}O_{6}$

Hence, empirical formula is $C_{3}H_{4}O_{3}$ and molecular formula is $C_{6}H_{8}O_{6}$

8 0

3 years ago

Determine how many moles are present in 523.46g of glucose, c6h12o6

Galina-37 [17]

1 mole C6H12O6 -------------- 180.15 g
? moles C6H12O6 ------------ 523.46 g

523.46 x 1 / 180.15 => <span>2.905 moles</span>

8 0

3 years ago

Determine the number of representative particles in the following: 0.35 mol zinc

Firdavs [7]

Answer:

36.4

Explanation:

8 0

3 years ago