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Answer:
Organic compounds can be synthesized in a laboratory setting
Organic compounds contain carbon
There are hundreds of thousands of organic compounds,
Explanation:
Organic compounds are compounds that are found in life i.e plants and animals. The bulk of compounds that makes up living organisms are called organic compounds.
The idea that organic compounds can only be found in living organisms has been proven wrong by the synthesis of urea in the laboratory.
Organic chemistry studies compounds of carbons with the exception of oxides, carbides and carbonates.
All these other compounds of carbon apart from the above listed ones are called organic compounds.
Answer:
12.2329 atm
Explanation:
Applying
PV = nRT.................... Equation 1
Make P the subject of the equation
P = (n/V)RT................ Equation 2
Where P = Osmotic pressure, (n/V) = Molarity of urea, T = Temperature, R = molar gas constant.
From the question,
Given: (n/V) = 0.5 M, T = 25°C = (273+25) = 298 K, R = 0.0821 Latm/mol.K
Substitute these values into equation 2
P = (0.5)(298)(0.0821)
P = 12.2329 atm
Answer:
ΔH = -55.92 kJ
Explanation:
<u>Step 1:</u> Data given
1 mol NaOH and 1 mol HBr initially at 22.5 °C are mixed in 100g of water
After mixing the temperature rises to 83 °C
Specific heat of the solution = 4.184 J/g °C
Molar mass of NaOH = 40 G/mol
Molar mass of HBr = 80.9 g/mol
<u>Step 2: </u>The balanced equation
NaOH + HBr → Na+(aq) + Br-(aq) + H2O(l)
<u>Step 3:</u> mass of NaOH
Mass = moles * Molar mass
Mass NaOH = 1 * 40 g/mol
Mass NaOH = 40 grams
Step 4: Mass of HBr
Mass HBr = 1 mol * 80.9 g/mol
Mass HBr = 80.9 grams
Step 5: Calculate ΔH
ΔH = m*c*ΔT
ΔH= (100 + 40 + 80.9) * 4.184 * (83-22.5)
ΔH= 220.9 * 4.184 * 60.5
ΔH= 55916.86 J = 55.92 kJ
Since this is an exothermic reaction, the change in enthalpy is negative.
ΔH = -55.92 kJ
