What are the major products when glucose is broken down in glycolysis?

A roller coaster track is 3,000 meters long. It takes 100 seconds totravel once around the roller coaster. What is the average s

postnew [5]

The rollercoaster went 200 miles.

3 0

2 years ago

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What are two processes that result in rocks being broken down into smaller pieces !?

Snowcat [4.5K]

<span>"Chemical weathering and physical weathering" would be the correct answer

Chemical weathering breaks down the bonds holding the rocks together, and the physical weathering will crush and break them apart.</span>

7 0

3 years ago

(b) The conductivity of a 0.01 mol dm–3 solution of a monobasic organic acid in water is 5.07 × 10–2 S m–1. If the molar conduct

Zarrin [17]

Explanation:

The given data is as follows.

$\Lambda^{o}_{m}$ (NaCl) = $1.264 \times 10^{-2}$

$\Lambda^{o}_{m}$ (H-O=C-ONO) = $1.046 \times 10^{-2}$

$\Lambda^{o}_{m}$ (HCl) = $4.261 \times 10^{-2}$

Conductivity of monobasic acid is $5.07 \times 10^{-2} S m^{-1}$

Concentration = 0.01 $mol/dm^{3}$

Therefore, molar conductivity ( $\Lambda_{m}$ ) of monobasic acid is calculated as follows.

$\Lambda_{m} = \frac{conductivity}{concentration}$

= $\frac{5.07 \times 10^{-2} S m^{-1}}{0.01 mol/dm^{3}}$

= $\frac{5.07 \times 10^{-2} S m^{-1}}{0.01 mol \times 10^{3}}$

= $5.07 \times 10^{-3} S m^{2} mol^{-1}$

Also, $\Lambda^{o}_{m}$ = $\Lambda^{o}_{m}_{(HCl)} + \Lambda^{o}_{m}_{(H-O=C-ONO)} - \Lambda^{o}_{m}_{(NaCl)}$

= $4.261 \times 10^{-2} + 1.046 \times 10^{-2} - 1.264 \times 10^{-2}$

= $4.043 \times 10^{-2} S m^{2} mol^{-1}$

Relation between degree of dissociation and molar conductivity is as follows.

$\alpha = \frac{\Lambda_{m}}{\Lambda^{o}_{m}}$

= $\frac{5.07 \times 10^{-2} S m^{-1}}{4.043 \times 10^{-2} S m^{2} mol^{-1}}$

= 0.1254

Whereas relation between acid dissociation constant and degree of dissociation is as follows.

K = $\frac{c \times \alpha^{2}}{1 - \alpha}$

Putting the values into the above formula we get the following.

K = $\frac{c \times \alpha^{2}}{1 - \alpha}$

= $\frac{0.01 \times (0.1254)^{2}}{1 - 0.1254}$

= $0.017973 \times 10^{-2}$

= $1.7973 \times 10^{-4}$

Hence, the acid dissociation constant is $1.7973 \times 10^{-4}$ .

Also, relation between $pK_{a}$ and $K_{a}$ is as follows.

$pK_{a} = -log K_{a}$

= $-log (1.7973 \times 10^{-4})$

= 3.7454

Therefore, value of $pK_{a}$ is 3.7454.

3 0

2 years ago

Write an informal definition of half-life.

Pavel [41]

the time required for the activity of a substance taken into the body to lose one half its initial effectiveness. Informal. a brief period during which something flourishes before dying out.

hope this helps ^^

6 0

2 years ago

When atp is hydrolyzed to power a condensation reaction, what happens to the phosphate molecule that is released?

Leto [7]

The phosphate molecule that is released it is coupled to a different ADP molecule to make new molecule of ATP.

Hydrolysis of high-energy compound (ATP) using water:

ATP + H₂O → ADP + Pi

ATP is short for adenosine triphosphate.

Hydrolysis is a reaction that breaks down the chemical bonds between molecules via the addition of a water molecule.

A condensation reaction is a reaction that joins two molecules in a chemical bond.

ATP is resynthesized in a condensation reaction that adds an inorganic phosphate group to ADP. The addition of a phosphate group is catalyzed by the enzyme ATP synthase.

More about potential energy: brainly.com/question/21175118

#SPJ4

5 0

1 year ago