One thing to notice in the question is, we are asked about molecular oxygen that has formula O2 not atomic oxygen O.
As we are asked about molecular oxygen, we will answer the question in terms of number of molecules that are present in 16 grams of molecular oxygen.
To get the number of molecules present in 16 grams of O2, we will use the formula:
No. of molecules = no. of moles x Avogadro's number (NA)----- eq 1)
As we know:
The number of moles = mass/ molar mass of molecule
Here we have been given mass already, 16 grams and the molar mass of O2 is 32 grams.
Putting the values in above formula:
= 16/32
= 0.5 moles
Putting the number of moles and Avogadro's number (6.02 * 10^23) in eq 1
No. of molecules = 0.5 x 6.02 * 10^23
=3.01 x 10^23 molecules
or 301,000,000,000,000,000,000,000 molecules
This means that 16 grams of 3.01 x 10^23 molecules of oxygen.
Hope it helps!
If you want the answer is centimeters is it going to be:
26.281 cm
If it make it easier for you to solve add 6.201 and 7.4 which will equal 13.601. Then add .68 to 13.601 which equals 14.281. Last add 12 to 14.281 which equals 26.281.
Hope this helps.
Carbon dioxide it should be water oxygen
Answer:
8.1433 g of XeF₆ are required.
Explanation:
Balanced chemical equation;
XeF₆ (s) + 3H₂ (g) → Xe (g) + 6HF (g)
Given data:
Volume of hydrogen = 0.579 L
Pressure = 4.46 atm
Temperature = 45 °C (45+273= 318 k)
Solution:
First of all we will calculate the moles of hydrogen
PV = nRT
n = PV/ RT
n = 4.46 atm × 0.579 L / 0.0821 atm. dm³. mol⁻¹. K⁻¹ × 318 K
n = 2.6 atm . L / 26.12 atm. dm³. mol⁻¹
n = 0.0995 mol
Mass of hydrogen:
Mass = moles × molar mass
Mass = 0.0995 mol × 2.016 g/mol
Mass = 0.2006 g
Now we will compare the moles of hydrogen with XeF₆ from balance chemical equation.
H₂ : XeF₆
3 : 1
0.0995 : 1/3× 0.0995 = 0.0332 mol
Now we will calculate the mass of XeF₆.
Mass = moles × molar mass
Mass = 0.0332 mol × 245.28 g/mol
Mass = 8.1433 g
I believe the answer would be 3( conserved)