Step-by-step explanation:
- 89
- 81
- 50
- 83
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<h2>hope it helps.</h2><h2>stay safe healthy and happy.</h2>
Given the data below <span>representing the body mass index (bmi) values for 20 females.
17.7 33.5 26.9 22.7 22.2 29.9 23.6 18.3 27.7 23.4 19.2 25.9 22.9 37.7 31.6 28.1 44.9 31.6 25.2 23.9
From the data above, we construct a frequency distribution beginning with a lower class limit of
15.0 and use a class width of 6.0 as follows:
Class iinterval: 15.0 - 21.0 21.0 - 27.0 27.0 - 33.0 33.0 - 39.0 39.0 - 45.0
Frequency: 3 9 5 2 1
From the frequency table, it can be seen that the frequencies started low, increased to a point and then decrease. It can also be seen that the highest frequency of the data is not at the center of the distribution, so the distribution is not symetric.
Therefore, the frequency
distribution does not appear to be roughly a normal distribution, because, "although the frequency start low, increase to some maximum, then decrease, the distribution is not symmetric."</span>
The quotient is x^3 + 4x^2 -x + 1.
Solution:
By polynomial grid division, we start by the divisor 3x + 10 placed on the column headings.
3x 10
x^3 3x^4
We know that 3x^4 must be in the top left which means that the first row entry must be x^3. So the row and column multiply to 3x^4. We use this to fill in all of the first row, multiplying x^3 by the terms of the column entries.
3x 10
x^3 3x^4 10x^3
4x^2
We now got 10x^3 though we want 22x^3. The next cubic entry must then be 12x^3 so that the overall sum is 22x^3.
3x 10
x^3 3x^4 10x^3
4x^2 12x^3
Now we have 40x^2, so the next quadratic entry must be -3x^2 so that the overall sum is 37x^2.
3x 10
x^3 3x^4 10x^3
4x^2 12x^3 40x^2
-x -3x^2 -10x
This time we have -10x, so the next linear entry must be 3x so that the overall sum is 7x.
3x 10
x^3 3x^4 10x^3
4x^2 12x^3 40x^2
-x -3x^2 -10x
1 3x 10
The bottom and final term is 10, which is our desired answer. Therefore, we can now read the quotient off the first column:
3x^4+22x^3+37x^2-7x+10 / 3x + 10 = x^3 + 4x^2 -x + 1
