Initially, an inductor with no resistance carries a constant current. Then the current is brought to a new constant value twice
1 answer:
Answer:
The emf in the inductor continues to be zero.
Explanation:
It is given that, an inductor with no resistance carries a constant current. Then the current is brought to a new constant value twice as large. Finally, the current is constant at its higher value. We know that the voltage across the inductor is given by :
is the change in current
Since, the change in current is constant, then the emf in the inductor continues to be zero. So, the correct option is (A).
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Complete Question:
In the same configuration of the previous problem 3, four long straight wires are perpendicular to the page, and their cross sections form a square of edge length a = 13.5 cm. Each wire carries 7.50 A, and the currents are out of the page in wires 1 and 4 and into the page in wires 2 and 3.
a) Draw a diagram in a (x,y) plane of the four wires with wire 4 perpendicular to the origin. Indicate the current's directions.
b) Draw a diagram of all magnetic fields produced at the position of wire 3 by the other three currents.
c) Draw a diagram of all magnetic forces produced at the position of wire 3 by the other three currents.
d) What are magnitude and direction of the net magnetic force per meter of wire length on wire 3?
Answer:
force, 1.318 ₓ 10⁻⁴
direction, 18.435°
Explanation:
The attached file gives a breakdown step by step solution to the questions
