Emf e = 11
r 1 = 3.0
r 2 = 3.0
r 3 = ?
The two in parallel are equivalent to 3 • 3/6 = 1.5 Ω
To have 2.4 volts across them, the current is I = 2.4/1.5 = 1.6 amps. and the unknown R = (11–2.4) / 1.6 = 5.375 Ω or 5.4 Ω
Answer:
50m; 0m/s.
Explanation:
Given the following data;
Initial velocity = 20m/s
Acceleration, a = - 4m/s²
Time, t = 5secs
To find the displacement, we would use the second equation of motion;
Substituting into the equation, we have;
S = 50m
Next, to find the final velocity, we would use the third equation of motion;
Where;
- V represents the final velocity measured in meter per seconds.
- U represents the initial velocity measured in meter per seconds.
- a represents acceleration measured in meters per seconds square.
<em>Substituting into the equation, we have;</em>
V = 0m/s
<em>Therefore, the displacement of the bus is 50m and its final velocity is 0m/s.</em>
The part B of the question is missing and it is;
b) What is the height between the two window ledges?
Answer:
A) 20.76 m/s
B) 161.52 m
Explanation:
A) To calculate the initial speed we use the formula from Newton's first law of motion:
v = u + at
Making u the subject gives;
u = v - at
Where;
v is the final velocity which is the speed when Jill sees the pot = 60 m/s
u is the initial velocity which is the speed when Jack sees the pot go by
t is the time between the two observed events = 4 s
a in this question is acceleration due to gravity = 9.81 m/s².
Plugging in the relevant values into the initial velocity equation gives;
u = 60 - (9.81 × 4)
u = 20.76 m/s
B) To get the height difference, we will use the formula;
(y1 - y0) = ut + ½at²
Thus, plugging in the relevant values, we have;
y1 - y0 = (20.76 × 4) + (½ × 9.81 × 4²)
(y1 - y0) = 161.52 m
Answer:
The force between two charges and the distance separating them.
Explanation:
Answer:
570 J
Explanation:
im sorry im not sure about the rest but i hope this helps
