Answer
given,
Time period= T = 1.5 s
If it's moving through equilibrium point at t₀= 0 with v = 1.0 m/s
v_max=1.00 m/s
we know,
v_ max=A ω
v = A sin (ωt)
-0.50= -1.00 sin (ωt)
sin (ωt) = 0.5
![\omega t = sin^{-1}(0.5)](https://tex.z-dn.net/?f=%5Comega%20t%20%3D%20sin%5E%7B-1%7D%280.5%29)
![\dfrac{2\pi}{T}\times t =0.524](https://tex.z-dn.net/?f=%5Cdfrac%7B2%5Cpi%7D%7BT%7D%5Ctimes%20t%20%3D0.524)
![\dfrac{2\pi}{1.5}\times t =0.524](https://tex.z-dn.net/?f=%5Cdfrac%7B2%5Cpi%7D%7B1.5%7D%5Ctimes%20t%20%3D0.524)
t = 0.125 s
we have time period T=1.5 it is the time to complete one oscillation
means from eq to right,then left,then eq,then left,then from right to eq
time taken for left = t/4 = 0.125/4 = 0.375 s
smallest value of time
=0.375 + 0.125
= 0.50 sec
<span>Quantitative. I hopes this helps you some!</span>
Answer:
Image distance is -52.5 cm
Image is virtual and forms on the same side of the lens and upright image is formed.
Explanation:
u = Object distance
v = Image distance
f = Focal length = 35
m = Magnification = 2.5
![m=-\frac{v}{u}\\\Rightarrow 2.5=-\frac{v}{u}\\\Rightarrow v=-2.5 u](https://tex.z-dn.net/?f=m%3D-%5Cfrac%7Bv%7D%7Bu%7D%5C%5C%5CRightarrow%202.5%3D-%5Cfrac%7Bv%7D%7Bu%7D%5C%5C%5CRightarrow%20v%3D-2.5%20u)
Lens equation
![\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{35}=\frac{1}{u}+\frac{1}{-2.5u}\\\Rightarrow \frac{1}{35}=\frac{3}{5u}\\\Rightarrow u=21\ cm](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bf%7D%3D%5Cfrac%7B1%7D%7Bu%7D%2B%5Cfrac%7B1%7D%7Bv%7D%5C%5C%5CRightarrow%20%5Cfrac%7B1%7D%7B35%7D%3D%5Cfrac%7B1%7D%7Bu%7D%2B%5Cfrac%7B1%7D%7B-2.5u%7D%5C%5C%5CRightarrow%20%5Cfrac%7B1%7D%7B35%7D%3D%5Cfrac%7B3%7D%7B5u%7D%5C%5C%5CRightarrow%20u%3D21%5C%20cm)
![v=-2.5\times 21=-52.5\ cm](https://tex.z-dn.net/?f=v%3D-2.5%5Ctimes%2021%3D-52.5%5C%20cm)
Image distance is -52.5 cm
Image is virtual and forms on the same side of the lens and upright image is formed.
The standard cell potential helps to determine the oxidative and reductive strength of species. All the species that lie below the Standard Hydrogen Electrode in the standard cell potential table are stong oxidizing agents and are highly electronegative while those that are above the Standard Hydrogen Electrode are either weak oxidants or reducing agents