3 years ago

PLEASE PLEASE PLEASE HELP!!

Mathematics

2 answers:

blsea [12.9K]3 years ago

5 0

Incomplete question..would please repost it

Lapatulllka [165]3 years ago

3 0

What's the problem?
I don't see it

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what is the common number to be subtracted from each term of the ratio 11:8 to get the new ratio 2:1.?

JulijaS [17]

Answer:

5 should be subtracted from each term

Step-by-step explanation:

$\frac{11-x}{8-x}=\frac{2}{1}$

Cross multiply,

1 * (11 - x) = 2*(8-x)

11 -x = 2*8 - 2*x

11 - x = 16 - 2x

Subtract 11 from both sides,

-x = 16 - 2x - 11

-x = 5 - 2x

Add 2x to both sides

-x +2x = 5 - 2 + 2x

x = 5

7 0

3 years ago

Simplify the expression: 5(x + 2) > 50

kondor19780726 [428]

Answer:

x >8

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Let f(x) = -x-1, h(x) = x-3/3 Find (f o h)(-1).

larisa86 [58]

(f o h) = -(x - 3/3) - 1
(f o h) = (-x + 3)/3 - 1
(f o h)(1) = (-1 + 3)/3 - 1
(f o h)(1) = 2/3 - 1
(f o h)(1) = -1/3

7 0

3 years ago

Answers options are 6/26 8/18 14/12 14/26 Pls help

prohojiy [21]

Answer:

14/26

Step-by-step explanation:

6+8=14

14+12=26

6 0

3 years ago

The question is:

saul85 [17]

$f(x) = \sqrt{x+1} \\ y = \sqrt{x+1} \ or \ y^2 = x+1 \ or \ x = y^2 - 1 \\ Therefore, \ f^{-1}(x)=x^2 - 1$

$(fof^{-1})(a) = f(f^{-1}(a))=f(a^2-1) \\ =\sqrt{a^2-1+1}=\sqrt{a^2}=a \\ \\ (f^{-1}of)(a)=f^{-1}(f(a))=f^{-1}(\sqrt{a+1})= \\ (\sqrt{a+1})^2-1 = a+1-1 = a$

Therefore, $(fof^{-1})(a) = (f^{-1}of)(a) = a$

8 0

3 years ago