Answer:
M₂ = 0.9 M
Explanation:
Given data:
Initial Volume = V₁ = 250 mL
Initial molarity = M₁= 3 M
Final volume = 850 mL
Final molarity = ?
Solution:
M₁V₁ = M₂V₂
M₂ = M₁V₁ /V₂
M₂ = 3 M × 250 mL / 850 mL
M₂ = 750 M / 850
M₂ = 0.9 M
Since the leaving ability of the halide ions increasees as the basicity of the halide decreases.
If the basicity of the halide decreases as the its conjugate acid is strong.
Since the pKa value of conjuage acid of haldie is 3, it is a weak acid. So, it halide is not a good leaving group.
Therefore the answer is No, because a good leaving group is the conjugate base of a strong acid. The halide not acidic enough to be a good leaving group.
<span> rate 3/1= square root of 32/x
square both sides
9/1=32x
x = 32/9
= 3.6
Must be He
molar mass =4
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Answer:
Then pressure will double
Explanation:
PV = nRT
P = nRT / V
If all other variables are kept constant, P will be proportional to n i.e
P1 / n1 = P2 / n2
n = 1
P1 = P
n2 = 2
P2 =?
P1 / n1 = P2 / n2
P /1 = P2/2
Cross multiply
P2 = 2P
Therefore, if an additional 1mole of the gas is added, the pressure will double