The mass lost in the process is 1.4 * 10^-5Kg.
<h3>What is the Einstein equation?</h3>
The Einstein equation is able to relate the mass lost to the energy that is evolved in a nuclear process.
Given that;
E = Δmc^2
Δm = E/c^2
Δm = 1.26 × 10^12 J/( 3 * 10^8)^2
Δm = 1.4 * 10^-5Kg
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Answer:
a) 0.925 mol Na2CO3 can be theoretically produced
b) 0.075 moles of the excess starting material remains
Explanation:
balaced chemical:
2 NaOH(s) + CO2(g) ↔ Na2CO3(s) + H2O(aq)
1.85n 1.00n Xn
moles theor. Na2CO3:
⇒ nNaCO3 = 1.85nNaOH * ( nNa2CO3 / 2nNaOH)
⇒ nNa2CO3 = 0.925nNa2CO3
moles of the excess:
⇒moles CO2 react = 1.85nNaOH * nCO2 / 2nNaOH = 0.925n CO2
⇒moles CO2 excess = 1.00n - 0.925n = 0.075n excess CO2
