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sdas [7]
3 years ago
13

Senioritis usually affects which of the following groups the most?

Computers and Technology
1 answer:
Dovator [93]3 years ago
6 0
Generally we'd need "the following" if the question asks about it. Senioritis usually affects high school seniors IIRC.
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Along with an ip address, a subnet mask, and a name server, the other thing required for a computer to operate on a network is a
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Along with an IP address, a subnet mask, and a name server, the other thing required for a computer to operate on a network is a primary gateway. The primary gateway acts as an access point which forwards information to another network or the internet.

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Which of the following is the most reliable way to check the accuracy of a website?
ELEN [110]

Answer:

Examine the sources cited by the website

Explanation:

Due to the ability for everyone to create a website, and that there are no governing standards on the quality of information given on websites, it is important when conducting research to ensure that the sources on the web are up to date, accurate, and provide an objective view

Therefore, it is important to go through and examine the website critically using the the following criteria

1) The website coverage

2) The currency of the website's information

3) Weather the website is objective or not

4) The identity of the author of the website and the ability to contact the author

5) The accuracy of the information contained in the website

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Computer A has an overall CPI of 1.3 and can be run at a clock rate of 600 MHz. Computer B has a CPI of 2.5 and can be run at a
kirill115 [55]

Answer:

Check the explanation

Explanation:

CPI means Clock cycle per Instruction

given Clock rate 600 MHz then clock time is Cー 1.67nSec clockrate 600M

Execution time is given by following Formula.

Execution Time(CPU time) = CPI*Instruction Count * clock time = \frac{CPI*Instruction Count}{ClockRate}

a)

for system A CPU time is 1.3 * 100, 000 600 106

= 216.67 micro sec.

b)

for system B CPU time is =\frac{2.5*100,000}{750*10^6}

= 333.33 micro sec

c) Since the system B is slower than system A, So the system A executes the given program in less time

Hence take CPU execution time of system B as CPU time of System A.

therefore

216.67 micro = =\frac{2.5*Instruction}{750*10^6}

Instructions = 216.67*750/2.5

= 65001

hence 65001 instruction are needed for executing program By system B. to complete the program as fast as system A

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who is that? ..........

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Advantages of a computer​
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It eases work.

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