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Komok [63]
3 years ago
10

In an experiment, a student dissolves 56.3g of MgCl2 in 0.12kg of solvent. What is the molality of this solution? Show your work

.
Chemistry
1 answer:
Kazeer [188]3 years ago
7 0

<u>Answer:</u> The molality of magnesium chloride is 4.93 m

<u>Explanation:</u>

To calculate the molality of solution, we use the equation:

Molality=\frac{m_{solute}}{M_{solute}\times W_{solvent}\text{ in kg}}

Where,

m_{solute} = Given mass of solute (MgCl_2) = 56.3 g

M_{solute} = Molar mass of solute (MgCl_2) = 95.2 g/mol

W_{solvent} = Mass of solvent = 0.12 kg

Putting values in above equation, we get:

\text{Molality of }MgCl_2=\frac{56.3}{95.2\times 0.12}\\\\\text{Molality of }MgCl_2=4.93m

Hence, the molality of magnesium chloride is 4.93 m

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<h3>Answer:</h3>

13 g CO₂

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<u>Stoichiometry</u>

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<u>Math</u>

<u>Pre-Algebra</u>

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<h3>Explanation:</h3>

<u>Step 1: Define</u>

<em>Identify variables</em>

[Given] 6.7 L O₂

[Solve] g O₂

<u>Step 2: Identify Conversions</u>

[STP] 22.4 L = 1 mol

[PT] Molar Mass of O: 16.00 g/mol

[PT] Molar Mass of C: 12.01 g/mol

Molar Mass of CO₂: 12.01 + 2(16.00) = 44.01 g/mol

<u>Step 3: Convert</u>

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Answer the following Question Down Below...
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The mass number of the atom is 21, the atomic number is 9, and the element is Fluorine. There are 9 protons, 9 electrons, 12 neutrons, and the elemental symbol is F.

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