Question

In an experiment, a student dissolves 56.3g of MgCl2 in 0.12kg of solvent. What is the molality of this solution? Show your work.

Answer 1

Answer: The molality of magnesium chloride is 4.93 m

Explanation:

To calculate the molality of solution, we use the equation:

$Molality=\frac{m_{solute}}{M_{solute}\times W_{solvent}\text{ in kg}}$

Where,

$m_{solute}$ = Given mass of solute $(MgCl_2)$ = 56.3 g

$M_{solute}$ = Molar mass of solute $(MgCl_2)$ = 95.2 g/mol

$W_{solvent}$ = Mass of solvent = 0.12 kg

Putting values in above equation, we get:

$\text{Molality of }MgCl_2=\frac{56.3}{95.2\times 0.12}\\\\\text{Molality of }MgCl_2=4.93m$

Hence, the molality of magnesium chloride is 4.93 m