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Komok [63]
3 years ago
10

In an experiment, a student dissolves 56.3g of MgCl2 in 0.12kg of solvent. What is the molality of this solution? Show your work

.
Chemistry
1 answer:
Kazeer [188]3 years ago
7 0

<u>Answer:</u> The molality of magnesium chloride is 4.93 m

<u>Explanation:</u>

To calculate the molality of solution, we use the equation:

Molality=\frac{m_{solute}}{M_{solute}\times W_{solvent}\text{ in kg}}

Where,

m_{solute} = Given mass of solute (MgCl_2) = 56.3 g

M_{solute} = Molar mass of solute (MgCl_2) = 95.2 g/mol

W_{solvent} = Mass of solvent = 0.12 kg

Putting values in above equation, we get:

\text{Molality of }MgCl_2=\frac{56.3}{95.2\times 0.12}\\\\\text{Molality of }MgCl_2=4.93m

Hence, the molality of magnesium chloride is 4.93 m

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50.0 g × 1 mol/46.07 g = 1.09 mol

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The molar ratio of CH₃CH₂OH to CH₃CH₂OCH₂CH₃ is 2:1. The moles of CH₃CH₂OCH₂CH₃ theoretically produced are 1/2 × 1.09 mol = 0.545 mol.

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<h3>Answer:</h3>

915 Joules

<h3>Explanation:</h3>
  • The heat of fusion is the heat that is required to convert a given mass of a substance from solid state to liquid state without change in temperature.
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