1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
leva [86]
3 years ago
9

For any set of n measurements, the fraction included in the interval y − ks to y + ks is at least 1 − 1 k2 . This result is know

n as Tchebysheff's theorem. A personnel manager for a certain industry has records of the number of employees absent per day. The average number absent is 8.5, and the standard deviation is 3.5. Because there are many days with zero, one, or two absent and only a few with more than ten absent, the frequency distribution is highly skewed. The manager wants to publish an interval in which at least 75% of these values lie. Use Tchebysheff's theorem to find such an interval.
Mathematics
1 answer:
Karo-lina-s [1.5K]3 years ago
7 0

Answer:

This interval is between 1.5 and 15.5.

Step-by-step explanation:

Tchebysheff's Theorem

The Tchebysheff's Theorem can also be applied to non-normal distribution. It states that:

At least 75% of the measures are within 2 standard deviations of the mean.

At least 89% of the measures are within 3 standard deviations of the mean.

An in general terms, the percentage of measures within k standard deviations of the mean is given by 100(1 - \frac{1}{k^{2}}).

In this question, we have that:

Mean = 8.5

Standard deviation = 3.5

The manager wants to publish an interval in which at least 75% of these values lie.

By the Tchebysheff's Theorem, at least 75% of the measures are within 2 standard deviations of the mean.

8.5 - 2*3.5 = 1.5

8.5 + 2*3.5 = 15.5

This interval is between 1.5 and 15.5.

You might be interested in
Decrease 220kg by 12.5%.<br><br> NEED HELPPP!
Serga [27]
Hmm try 192.5 I think that’s right
6 0
3 years ago
Read 2 more answers
Find the volume of the prism.<br><br><br><br> The volume is <br> cubic inches.
Liono4ka [1.6K]

<em>So</em><em> </em><em>the</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>3</em><em>/</em><em>1</em><em>0</em><em> </em><em>cubic</em><em> </em><em>inches</em><em>.</em>

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>you</em>

<em>Good</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>

4 0
3 years ago
Read 2 more answers
What graph passes the vertical line test?
Marianna [84]

Answer:

The fourth image, or D.

Why?

If you had a ruler and placed it on the grid vertically and moved the ruler left to right, pictures A, B, and C, all have two points that lay on the same X point.

Picture D is the only one that has no points that lay on the same X point, thus making it the right answer.

Thank you for reading into this.

(Hope this helps you! ^^)

5 0
3 years ago
Read 2 more answers
A large corporation starts at time t = 0 to invest part of its receipts continuously at a rate of P dollars per year in a fund f
Andrews [41]

Answer:

A = \frac{P}{r}\left( e^{rt} -1 \right)

Step-by-step explanation:

This is <em>a separable differential equation</em>. Rearranging terms in the equation gives

                                                \frac{dA}{rA+P} = dt

Integration on both sides gives

                                            \int \frac{dA}{rA+P} = \int  dt

where c is a constant of integration.

The steps for solving the integral on the right hand side are presented below.

                               \int \frac{dA}{rA+P} = \begin{vmatrix} rA+P = m \implies rdA = dm\end{vmatrix} \\\\\phantom{\int \frac{dA}{rA+P} } = \int \frac{1}{m} \frac{1}{r} \, dm \\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \int \frac{1}{m} \, dm\\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |m| + c \\\\&\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |rA+P| +c

Therefore,

                                        \frac{1}{r} \ln |rA+P| = t+c

Multiply both sides by r.

                               \ln |rA+P| = rt+c_1, \quad c_1 := rc

By taking exponents, we obtain

      e^{\ln |rA+P|} = e^{rt+c_1} \implies  |rA+P| = e^{rt} \cdot e^{c_1} rA+P = Ce^{rt}, \quad C:= \pm e^{c_1}

Isolate A.

                 rA+P = Ce^{rt} \implies rA = Ce^{rt} - P \implies A = \frac{C}{r}e^{rt} - \frac{P}{r}

Since A = 0  when t=0, we obtain an initial condition A(0) = 0.

We can use it to find the numeric value of the constant c.

Substituting 0 for A and t in the equation gives

                         0 = \frac{C}{r}e^{0} - \frac{P}{r} \implies \frac{P}{r} = \frac{C}{r} \implies C=P

Therefore, the solution of the given differential equation is

                                   A = \frac{P}{r}e^{rt} - \frac{P}{r} = \frac{P}{r}\left( e^{rt} -1 \right)

4 0
3 years ago
Please help its do now<br> ...<br> ..<br> .
never [62]

Answer:

21.

Step-by-step explanation:

3 0
2 years ago
Other questions:
  • Brainiest to who ever answers first
    13·1 answer
  • 4x(7x+5) what is the answer
    13·2 answers
  • What is the solution to the compound inequality in interval notation?
    12·1 answer
  • Round 92.471 to the nearest tenth
    7·2 answers
  • This extreme value problem has a solution with both a maximum value and a minimum value. use lagrange multipliers to find the ex
    13·1 answer
  • Im2 finding angles using algebra <br>find: m&lt;BEC ​
    5·1 answer
  • The function ​f(x)​ is the height of an object x seconds after it is thrown in the air. The object reaches its maximum height in
    14·1 answer
  • Can some one help me with this, I can't get it, and i'll give brainliest, 5 star, and all the good stuff.
    12·1 answer
  • (p^2-7pq-q^2)+(-3p^2-2pq+7q^2)<br><br>​
    13·1 answer
  • NEED HELP ASAP PLZ HELP
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!