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pentagon [3]
3 years ago
10

Janey paid $200 of a $250 bill. What percent of the bill did she pay?

Mathematics
1 answer:
makvit [3.9K]3 years ago
4 0
I'm pretty sure it's 80% because 10% of 250 is 25!
20% 50
30% 75
40% 100
50% 125
60% 150
70% 175
80% 200!
90% 225
100% 250!
So the answer is 80%! Hope this helped!
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Suppose you need to get the dent in your car fixed. You see the ads in the newspaper above (mikes repair shop $100 service charg
Norma-Jean [14]

Answer:

<em>Total Cost at Amy's shop is $280 which is less than the total cost at Mike's shop which is $295, so I will take the car to Amy's shop</em>

<em>Point of intersection: (x,y) = (4,360)</em>

Explanation:

Part 1 )

Let x = number of hours worked

Let y = total cost to you

Determining where to take the car:

<em>Total Cost at Amy's shop is $280 which is less than the total cost at Mike's shop which is $295</em>

Mike's repair shop:

Service fee: $100

Per hour rate: $65

Let x is the number of hours worked on. Total cost will be equal to the service fee plus hourly charges. Charges per an hour are $65, so for x hours the charges will be 65x.

Therefore, total cost for Amy's repair shop can be written as:

y = 100 + 65x ------(1)

For 3 hours work: y = 100 + 65(3)

<em>Cost at Mike's, y = $100 + $195 = $295</em>


<em>Amy's repair shop: </em>

Service fee: $40

Per hour rate: $80

Charges per an hour are $40, so for x hours the charges will be 80x.

Therefore, total cost for Amy's repair shop can be written as:

y = 40 + 80x ------(2)

For 3 hours work: x = 3

y = 40 + 80(3)

<em>Cost at Amy's, y  = $40 + $240 = $280</em>


<em>Part 2)</em>

<em>Find the point of intersection</em>

<em>Using elimination method:</em>

<em>y = 100 + 65 x    ------1</em>

<em>y = 40 + 80x      ------2</em>

<em>As the y coefficients are equal we will subtract eq1 from eq2</em>

<em>y - y = 40 + 80x - 100 - 65x</em>

<em>0 = -60 + 15x</em>

60 = 15x

x = \frac{60}{4}

x = 4

put x = 4 in eq 1

we get y = 100 + 65 (4) = 100 + 260 = 360

x = 4, y = 360

Point of intersection: (x,y) = (4,360)



8 0
3 years ago
3(p-3) – 5p&gt;-3p- 6<br> How do u solve?
vampirchik [111]

Answer:

p>3

Step-by-step explanation:

<=> 3p - 9 - 5p > -3p - 6

<=> -2p + 3p > -6 + 9

<=> p > 3

5 0
3 years ago
London purchased 4 3/4 pints of ice cream for a party. If each guest will be served exactly 2/3 pint of ice cream, what is the g
lara [203]

Answer:

7 persons

Step-by-step explanations:

If 4¾ pints of ice cream is available or the server and each person is expected to have a share of at least 2/3 pints.

The maximum number of people that will be able to get at least the supposed 2/3 pints will be gotten by dividing the total amounts of pints of ice cream by the amount that each person is expected to receive.

4¾ is the same as 19/4 or 4.75 and is divided by 2/3 or 0.6666666

19/4 ÷ 2/3

= 7⅛

But since ⅛ of a person doesn't exist,we have to discard it.

So therefore, the maximum number of persons that got a share of the ice cream is 7 persons

4 0
3 years ago
Read 2 more answers
Choose the correct simplification of the expression (−2x + 10y)(4x − 6y).
Korolek [52]
(-2x + 10y)(4x - 6y) =
-2x(4x - 6y) + 10y(4x - 6y) =
-8x^2 + 12xy + 40xy - 60y^2 =
-8x^2 + 52xy - 60y^2 <==
3 0
3 years ago
Read 2 more answers
I need help with these questions.
Ivanshal [37]

Answer:

  • See below

Step-by-step explanation:

<h3>Q13</h3>

The greater the angle the greater the opposite side

<u>Sides in ascending order:</u>

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<u>Angles in same order</u>

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<h3>Q14</h3>

<u>As above, sides in ascending order:</u>

  • AB = 15, AC = 16, BC = 17

<u>Angles in same order</u>

  • ∠C, ∠B, ∠A
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<u>Exterior angle equals to sum of non-adjacent interior angles</u>

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  • x = 142° - 66°
  • x = 76°
<h3>Q16</h3>

<u>Same subject and isosceles triangle:</u>

  • x + x = 158°
  • 2x = 158°
  • x = 79°
<h3>Q17</h3>

<u>Same subject</u>

  • m∠QSR = m∠QPS + m∠PQS
  • 2x = x + m∠PQS
  • m∠PQS = 2x - x
  • m∠PQS = x

ΔPQS has two angles with the measure of x, hence their opposite sides are congruent and the triangle is isosceles

7 0
3 years ago
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