If you launch the cannonball from the ground instead (hi=0), what does that change in the original equation?
1 answer:
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The complete question is
"Find the general solution of the given differential equation
y''-y=0, y1(t)=e^t , y2(t)=cosht
The function is the solution of the given differential equation.
The function y(t)=cosht is the solution of given differential equation.
<h3>What is a function?</h3>
The function is a type of relation, or rule, that maps one input to specific single output.
Given;
Given differential equations are,
y''-y = 0
So that,
Substitute values in the given differential equation.
Therefore, the function is the solution of the given differential equation.
Another function;
So that,
Hence, function y(t)=cosht is solution of given differential equation.
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