Question

Write the equation of the line that passes through (3, 4) and (2, −1) in slope-intercept form.

Answer 1

Answer:

Option C

y=5x-11

Step-by-step explanation:

We first find the gradient,m, of the line that passes through the points (3,4) and (2,-1)

Let

x=3

y=4

$x_1=2$

$y_1=-1$

$m=\frac{y - y_1}{x - x_1}$

By substitution,

$m=\frac{4-(-1)}{3-2}=\frac{4 + 1}{1} = \frac{5}{1}=5$

Putting that m=5, x=3 and y=4 into the general equation,

y=mx+c

This implies that

4=5(3)+c

4=15+c

4-15=c

c=-11

The equation of the line is given as

y=mx+c

where m=5 and c=-11

Hence y=5x-11