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yanalaym [24]
4 years ago
12

Need help ASAP What are the domain and range of the function

Mathematics
1 answer:
valina [46]4 years ago
7 0
The line seemingly keeps going infinitely in both directions so y,xER
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Which equation does the graph below represent?
Svetllana [295]
It represents y = -3x
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What is the area of this polygon?
Kobotan [32]
The answer is C; 35.5 units^2
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Find the area of each regular polygon. Round your answer to the nearest tenth if necessary.
tatuchka [14]

*I am assuming that the hexagons in all questions are regular and the triangle in (24) is equilateral*

(21)

Area of a Regular Hexagon: \frac{3\sqrt{3}}{2}(side)^{2} = \frac{3\sqrt{3}}{2}*(\frac{20\sqrt{3} }{3} )^{2} =200\sqrt{3} square units

(22)

Similar to (21)

Area = 216\sqrt{3} square units

(23)

For this case, we will have to consider the relation between the side and inradius of the hexagon. Since, a hexagon is basically a combination of six equilateral triangles, the inradius of the hexagon is basically the altitude of one of the six equilateral triangles. The relation between altitude of an equilateral triangle and its side is given by:

altitude=\frac{\sqrt{3}}{2}*side

side = \frac{36}{\sqrt{3}}

Hence, area of the hexagon will be: 648\sqrt{3} square units

(24)

Given is the inradius of an equilateral triangle.

Inradius = \frac{\sqrt{3}}{6}*side

Substituting the value of inradius and calculating the length of the side of the equilateral triangle:

Side = 16 units

Area of equilateral triangle = \frac{\sqrt{3}}{4}*(side)^{2} = \frac{\sqrt{3}}{4}*256 = 64\sqrt{3} square units

4 0
3 years ago
Y=4 -2x<br> у = -5 + 4х<br> ||
kolezko [41]

Answer:

y=1

Step-by-step explanation:

y= 4 - 2x

y= -5 + 4x

4 - 2x = -5 + 4x

4 + 5 = 4x +2x

9 = 6x

9/6 = x

3/2 = x

y= 4 -2(3/2)

y = 4 - 3

y = 1

5 0
3 years ago
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