1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nonamiya [84]
3 years ago
10

What is a common use for the physicians Desk Reference PDR

Physics
1 answer:
melamori03 [73]3 years ago
7 0

The PDR is  a thick volume that commonly used to provide guidance for prescription drugs available in the United states. The PDR is the most commonly used drug reference . The information is the same as the leaflet found in the drug package also known as the package insert.  Drug companies pay to have their drugs included, so many generic medicines will not be found in the book.

For over 60 years, physicians and researchers have turned to PDR for the latest word on prescription drugs. It includes comprehensive and up-to-date information on more than 4000 FDA approved drugs.

You might be interested in
The fast server in women's tennis is Venus Williams, who recorded a serve of 130 mi/h (209 km/h) in 2007. If her racket pushed o
lidiya [134]
Use the formulav^2 = u^2 + 2*a*swhere v is the final velocity of the ballu is the initial velocity of the balls is the displacement of the balla is the acceleration 
Givenv=130u=0s=0.1a=?
130^2 = 0^2 + 2a(0.1)solve for a
a = 84500 m/s2
5 0
3 years ago
What direction is the force of gravity?<br> up<br> down<br> neither up nor down
Novay_Z [31]
The force of gravity is down
8 0
3 years ago
Read 2 more answers
If it had been thrown with twice the speed in the same direction, it would have hit the ground in If it had been thrown with twi
Semmy [17]

Answer:

The ball will reach the ground in 0.8s

Option C

Explanation:

Given:

- Takes t = 0.8 s for ball to reach ground when thrown horizontal from top of a building.

Find:

If it had been thrown with twice the speed in the same direction, it would have hit the ground in how many second.

Solution:

- We know that the amount of time taken to hit the ground is determined by the vertical distance i.e height at which it is thrown. The displacement of ball from top is given by:

                                    S_y = S_o + V_i,y*t + 0.5*g*t^2

- We know that the S_o = height of the building.

 We also know that the ball os thrown horizontally; hence, y-component of initial velocity is zero. V_y,i = 0

                                    0 = h + 0 + 0.5*g*t^2

- Hence, the time taken t is:

                                    t = sqrt ( 2h / g)

- The time taken to reach the ground is independent of the initial speed. Hence, the ball will reach the ground in 0.8s .

7 0
3 years ago
A train travels 600 km in one hour. What is the trains velocity in meters/second
eimsori [14]

v= s/t

600 ÷ 60

10 m/s

4 0
4 years ago
Read 2 more answers
A 90 kg ice skater moving at 12.0 m/s on the ice encounters a region of roughed up ice with a coefficient of kinetic friction of
balandron [24]

Answer:

The skater covers a distance of <u>15 m</u> before stopping.

Explanation:

Let the distance traveled before stopping be 'd' m.

Given:

Mass of the skater (m) = 90 kg

Initial velocity of the skater (u) = 12.0 m/s

Final velocity of the skater (v) = 0 m/s (Stops finally)

Coefficient of kinetic friction (μ) = 0.490

Acceleration due to gravity (g) = 9.8 m/s²

Now, we know that, from work-energy theorem, the work done by the net force on a body is equal to the change in its kinetic energy.

Here, the net force acting on the skater is only frictional force which acts in the direction opposite to motion.

Frictional force is given as:

f=\mu N

Where, 'N' is the normal force acting on the skater. As there is no vertical motion, N=mg

∴ f=\mu mg=0.490\times 90\times 9.8=432.18\ N

Now, work done by friction is a negative work as friction and displacement are in opposite direction and is given as:

W=-fd=-432.18d

Now, change in kinetic energy is given as:

\Delta K=\frac{1}{2}m(v^2-u^2)\\\\\Delta K=\frac{1}{2}\times 90(0-12^2)\\\\\Delta K=45\times (-144)=-6480\ J

Therefore, from work-energy theorem,

W=\Delta K\\\\-432.18d=6480\\\\d=\frac{6480}{432.18}\\\\d=14.99\approx 15\ m

Hence, the skater covers a distance of 15 m before stopping.

7 0
3 years ago
Other questions:
  • Where is the location of a proton, and neutron?
    15·2 answers
  • If a 50 tooth sprocket turns at a speed of 20 rpm how many rpm will a 30 tooth sprocket turn
    15·1 answer
  • A phone cord is 2.89 m long. The cord has a mass of 0.258 kg. A transverse wave pulse is produced by plucking one end of the tau
    9·1 answer
  • An airplane starts from rest and reaches a takeoff velocity of 60.0m/s due north in 4.0s. How far has it traveled before take of
    14·1 answer
  • HELPPPPPPPPPPPPPPPPPPPPP
    13·2 answers
  • What does histogram mean
    12·2 answers
  • Look at the circuit diagram. What type of circuit is shown? A) open series circuit B) closed parallel circuit C) closed series c
    8·1 answer
  • 6. A _______ forms a pattern that resembles an animal, mythological character, or object.
    12·1 answer
  • Draw a series circuit using Two 1.5 V cells ,a bulb, an ammeter and a voltmeter
    11·1 answer
  • A long uniform board weighs 52.8 N (10.6 lbs) rests on a support at its mid point. Two children weighing 206.0 N (41.2 lbs) and
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!