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3 years ago

9

A phone cord is 2.89 m long. The cord has a mass of 0.258 kg. A transverse wave pulse is produced by plucking one end of the tau

tcord. The pulse makes four trips down and back along the cord in 0.737 s. What is the tension in the cord

1 answer:

Aleksandr [31]3 years ago

8 0

Answer:

$T =87.87\ N$

Explanation:

Given,

Length , l=2.89 m

Mass , M=0.258 Kg

Now, displacement $d=4(2 \times 2.89) m$

$=23.12 m$

Velocity of waves

$v=\sqrt{T / \mu}$

$\mu=\frac{0.258}{2.89 }$

$=0.0893$

Now, velocity, $v=\frac{d}{t}=\frac{23.12}{0.737 s}$

$=31.37 m/s$

The tension

$T=v^{2} \mu=31.37 \times 31.37 \times 0.0893$

$T =87.87\ N$

Tension in the chord is equal to $T =87.87\ N$

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The tibia is a lower leg bone (shin bone) in a human. The maximum strain that the tibia can experience before fracturing corresp

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Answer:

a

$k = 11600000 N/m$

b

$\Delta L = 3.2323 *10^{-5} \ m$

c

$F = 3750.28 \ N$

Explanation:

From the question we are told that

The Young modulus is $E = 1.4 *10^{10} \ N/m^2$

The length is $L = 0.35 \ m$

The area is $2.9 \ cm^2 = 2.9 *10^{-4} \ m ^2$

Generally the force acting on the tibia is mathematically represented as

$F = \frac{E * A * \Delta L }{L}$ derived from young modulus equation

Now this force can also be mathematically represented as

$F = k * \Delta L$

So

$k = \frac{E * A }{L}$

substituting values

$k = \frac{1.4 *10^{10} * 2.9 *10^{-4} }{ 0.35}$

$k = 11600000 N/m$

Since the tibia support half the weight then the force experienced by the tibia is

$F_k = \frac{750 }{2} = 375 \ N$

From the above equation the extension (compression) is mathematically represented as

$\Delta L = \frac{ F_k * L }{ A * E }$

substituting values

$\Delta L = \frac{ 375 * 0.35 }{ (2.9 *10^{-4}) * 1.4*10^{10} }$

$\Delta L = 3.2323 *10^{-5} \ m$

From the above equation the maximum force is

$F = \frac{1.4*10^{10} * (2.9*10^{-4}) * 3.233*10^{-5} }{ 0.35}$

$F = 3750.28 \ N$

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8) Calculate the kinetic energy of a truck that has a mass of 6100 kg and is moving at 55 m/s.

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Explanation:

The kinetic energy of an object can be found by using the formula

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3 years ago

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1. Faça as transformações:

zhannawk [14.2K]

Answer:

$seconds (s) = hours (h) *3,600 ; h = \frac{s}{3,600} \\g = kg * 1,000; kg = \frac{g}{1,000} \\cm = \frac{m}{100};m = cm * 100$

1. a) 0.5 h = 1,800 s

h) 20 cm = 0.2 m

b) 2.0 h = 7,200 s

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c) 3.5 h = 12,600 s

j) 1.5 kg = 1,500 g

d) 1/4 h = 900 s

k) 450.0 g = 0.45 kg

e) 3.0 m = 300 cm

l) 20.0 g = 0.02 kg

f) 2.5 m = 250 cm

m) 500.0 g = 0.5 kg

g) 0.5 m = 500 mm

n) 1000.0 g = 1 kg

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2 years ago