Answer:
Option A
The apparent change in frequency of waves due to the motion of a source
Explanation:
Doppler effect is the apparent change in frequency of waves due to the motion of a source. Doppler effect occurs when the source of waves moves towards the observer which causes emission of successive wave crests to be closer to the observer compared to the previous wave crest. This phenomenon was named after Austrian Physicist called Christian Doppler
Answer:
if you only have to control your chakra and know how to get all your vibes to pass it to objects and it takes time to practice
Answer:
a) k = 891.82 N/m
b) e = 0.0143 m = 1.43 cm
c) W = 5.02 J
Explanation:
Step 1: Data given
Mass = 2.60 kg
the spring stretches 2.86 cm = 0.0286
Step 2: What is the force constant of the spring?
Force constant, k = force applied / extension produced
k = (2.60kg * 9.81N/kg) / 0.0326 m
k = 891.82 N/m
b) If the 2.60-kg object is removed, how far will the spring stretch if a 1.30-kg block is hung on it
Extension = F/k = (1.30 kg * 9.81) / 891.82 = 0.0143 m = 1.43 cm
Half the mass means half the extension
c) How much work must an external agent do to stretch the same spring 7.50 cm from its unstretched position?
W = average force used * distance
W = 1/2 * k*e * e = 1/2 k*e²
W = 1/2 * 891.82 * (0.075)² = W = 5.02 J
Friction I believe is the answer
hope this helps
Explanation:
P₁ = P₂ + ρgh
g is the acceleration due to gravity
ρ is the density of the fluid
h is the depth of the fluid
P₁ is the pressure at that depth
P₂ is the pressure at the surface
P₁ and P₂ can either be absolute pressures or gauge pressures, but they must match.
For example, if you wanted to find the <em>absolute</em> pressure at the bottom of an <em>open</em> tank, you would use P₂ = Patm = 14.7 psi or 101.3 kPa.
If instead you wanted to find the <em>gauge</em> pressure, you would use P₂ − Patm = 0 psi or 0 kPa.
If the tank is sealed and pressurized, you would use the P₂ of the tank.
