Can u guys PLEASE answer this question ASAP. A line passes through the point (2,4) and has a gradient 2. Find the y-coordinate o
f the point on the line when x=3
1 answer:
y=2
Step-by-step explanation:
Make an equation of straight line by using the formula :y= mx+c
put the x-value of point (2,4) which is 2 and the gradient,m which is 2 into the straight line equation:
y=2x +c
So you need to find the y-intercept to complete the equation, therefore:
when y=0,
0=2(2)+c
c=-4
next the question ask to find the y-coordinate when x =3, therefore you just need to replace x in the equation with 3:
y=2(3)-4
y=4
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2x^2+4x-6=0
(2x^2+6x)(-2x-6)
2x(x+3) -2(x+3)
(2x-2)=0 (x+3)=0
x= 1 x=-3
What are you trying to say here? Can you explain the question?
Answer:
12y-3=2(5y+1/2)
12y-3=10y+1
12y-10y-3=1
12y-10y=1+3
2y=1+3
2y=4
y=2
Step-by-step explanation:
The answer to your question is 9,9
Answer:
6.5%
Step-by-step explanation:
I = prt
5616 = 7200 × r × 12
r = 5616/(7200 × 12)
r = 0.065
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