Answer:
-5x^2-32x+13
Step-by-step explanation:
(3-13x-7x)-(5x^2+12x-10)
3-20x-5x^2-12x+10
-5x^2-32x+13
For this case we have the following equation:
h = -16t2 + 32t + 6
Deriving we have:
h '= -32t + 32
Equaling to zero:
-32t + 32 = 0
We clear the time:
t = 32/32
t = 1 s
We are now looking for the maximum height:
h (1) = -16 * (1) ^ 2 + 32 * (1) + 6
h (1) = 22 feet
Answer:
The ball reaches its maximum height in:
t = 1 s
The ball's maximum height is:
h (1) = 22 feet
option: 22 ft, 1 s
Answer:
3 is not a like term because it isn't an x term, it doesn't have an x variable while the other terms do.
6/11 is the answer.
Hoped this helped!
