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3 years ago

What expression is equivalent to x^6-9

Mathematics

1 answer:

Sergeu [11.5K]3 years ago

7 0

Answer:

x^6-9 = x^-3 = 1/x^2

Step-by-step explanation:

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Eddi Din [679]

Answer:

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Vince has a rectangular rug in his room with an area of 10 ft the length of the rug is 18 inches longer than the width what coul

aev [14]

The length of the rug is 4 ft.

The width of the rug is 2.5 ft.

Explanation:

The area of the rug is 10 ft.

The length of the rug be l.

Let us convert the inches to feet.

Thus, $18 inches = 1.5 ft$

Thus, the length of the rug is $l=1.5+w$

Let the width of the rug be w.

Substituting these values in the formula of area of the rectangle, we get,

$A=length\times width$

$10=(1.5+w)(w)\\10=1.5w+w^2\\w^2+1.5w-10=0$

Solving the expression using the quadratic formula,

$w=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Substituting the values, we have,

$$w=\frac{-15 \pm \sqrt{15^{2}-4 \cdot 10(-100)}}{2 \cdot 10}\\$

$w=\frac{-15 \pm \sqrt{4225}}{20}$

$w=\frac{-15 \pm 65}{2 0}$

Thus,

$w=\frac{-15 + 65}{2 0}\\w=\frac{50}{20} \\w=2.5$ and $w=\frac{-15 - 65}{2 0}\\w=\frac{-80}{20} \\w=-4$

Since, the value of w cannot be negative, the value of w is 2.5ft

Thus, the width of the rug is 2.5ft

Substituting $w=2.5$ in $l=1.5+w$ , we get,

$l=1.5+2.5\\l=4$

Thus, the length of the rug is 4 ft.

4 0

3 years ago

If shoes are $20 each and the markup is 150%, how much will that cost?

MArishka [77]

150% to decimal = 1.50 since 100% = 1
1.50 x 20 = 30
30 + 20 = 50

3 0

3 years ago

Factor completely: −2x3 + 6x2

Pavel [41]

Correct answer is C.

$-2x^3+6x^2 \\-2x^2x+2x^23 \\2x^2(-x+3) \\2x^2(-(x-3)) \\-2x^2(x-3)$

4 0

3 years ago

Find the dimensions of a rectangle with a perimeter of 52cm if it’s length is 4cm more than its width

Zina [86]

So the perimeter(P) of a rectangle would be:
P= 2L+2W
L being the length and W being the width.
The problem says the length is 4cm more than the width, so L= 4+W.
So if we substitute L with 4+W, we get:
P= 2(4+W) + 2W
Use the Distributive Property
P= 8+2W+2W
Combine like terms
P=8+4W
Since we're given the perimeter, we could replace P with 52. So:
52=8+4W
Subtract 8 to both sides
44=4W
Divide 4 to both sides
11=W
Therefore, the width is 11cm
And since the length is 4cm more than the width, we could add 4cm to 11cm to find that the length is 15cm
Thus, the dimensions of the rectangle are 15cm by 11cm

5 0

3 years ago