A. $7.40
Adding $3.14 to $0.67 equals $3.81
You then could add $2.45 to $3.81 and get $6.26
Finally you add $1.14 to $6.26 and get $7.40
Group and factor/undistribute
(x^2y^3-2y^3)+(-2x^2+4)
(y^3)(x^2-2)+(-2)(x^2-2)
see the (x^2-2) is common term so undistribute
(x^2-2)(y^2-2)
last one
Answer:
7
Step-by-step explanation:
1) for '8'; '3'; and '10':
8/2+3+3=10
2) for '2'; '5' and '11':
2/1+5+5=11
3) for '6'; '2' and '?':
6/2+2+2=7
Answer:
98child tickets were sold that day
Step by step Explanation:
Let the number of children= A of the number of adult
Then
6.20C + 9.50A = 1082.0
From the question it was said that four times as many adult tickets as child tickets were sold which implies that number of adult was FOUR times the children, then we can say
A= 4C
Then substitute into the above equation
6.20C + 9.50A = 1082.0
6.20C + 9.50(4C) = 1082.0
6.20C + 38C= 1082.0
44.2C =1082.0
C= 24.48
But we know that
A= 4C
A=4* 24.48
A= 97.9
Therefore ,98child tickets were sold that day
Answer:
1/4= 25%
Step-by-step explanation:
