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Shalnov [3]
4 years ago
9

An object is moving with constant non-zero velocity. Which of the following statements about it must be true?

Physics
1 answer:
melisa1 [442]4 years ago
5 0

Answer:

The net force on the object is zero.

Explanation:

An object is moving with constant non-zero velocity. If velocity is constant, it means that the change in velocity is equal to 0. As a result, acceleration of the object is equal to 0. Net force is the product of mass and acceleration. Hence, the correct option is (d) "The net force on the object is zero".

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you push a ball to star it rolling along a "perfectly frictionless" surface. How far will the ball roll
-BARSIC- [3]
Technically, it should roll forever.
6 0
3 years ago
What is the power dissipated by the parallel resistor circuit shown above?
MatroZZZ [7]
One formula for power is

P = (voltage squared)/(resistance).

Resistance of 3 equal resistors in parallel is 1/3 of the value = 100/3 ohms.

Power = (40^2)/ (100/3)

. = (1600 • 3) / (100)

. =. 48 watts .
3 0
4 years ago
Given that the concentration of bovine carbonic anhydrase is 3.3 pmol ⋅ L − 1 and R max ( V max ) = 222 μmol ⋅ L − 1 ⋅ s − 1 , d
LuckyWell [14K]

Answer:

The turnover number of the enzyme molecule bovine carbonic anhydrase = 67,272,727.27 s^–1.

Explanation:

Given:

The concentration of bovine carbonic anhydrase = total enzyme concentration = Et = 3.3 pmol⋅L^–1 = 3.3 × 10^–12 mol.L^–1

The maximum rate of reaction = Rmax (Vmax) = 222 μmol⋅L^–1⋅s^–1 = 222 × 10^–6 mol.L^–1⋅s^–1

The formula for the turnover number of an enzyme (kcat, or catalytic rate constant) = Rmax ÷ Et = 222 × 10^–6 mol.L^–1⋅s^–1 ÷ 3.3 × 10^–12 mol.L^–1 = 67,272,727.27 s^–1

Therefore, the turnover number of the enzyme molecule bovine carbonic anhydrase = 67,272,727.27 s^–1

3 0
4 years ago
Answer <br> A<br> B<br> C<br> D and <br> E
harina [27]

Answer:

what is the question I cannot click the

Explanation:

4 0
3 years ago
A meter rule balance on a knife headge at the 55cm mark wheb a mass of 40g from 995cm .find the mass of the meter rule.
umka2103 [35]

Answer:

Let the weight of the ruler be X.

Now X acts in the middle, so we have 55-50 = 50cm

Since left hand movement= right hand movement

X(55-50)=90(95-55)

5X= 90×40

X=320cm

Hence the weight of the ruler is 320g

Explanation:

7 0
3 years ago
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