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3 years ago

What is the chemical name for the balanced equation? 2Al+3Pb(NO3)2=2Al(NO3)3+3Pb

Chemistry

1 answer:

Zigmanuir [339]3 years ago

8 0

The chemical name for reactant side:

Al - Aluminium, Pb(NO3)2 - Lead(II) nitrate.

The chemical name for product side:

Al(NO3)3 - Aluminium nitrate, Pb - lead.

<u>Explanation</u>:

This is an oxidation-reduction (redox) reaction:

3 $Pb^{II}$ + 6 e- → 3 $Pb^{o}$ (reduction)

2 $Al^{o}$ - 6 e- → 2 $Al^{III}$ (oxidation)

Pb(NO3)2 is an oxidizing agent, Al is a reducing agent.

Reactants:

Al uminium

Names: Aluminum, Aluminium powder, Al

Appearance: Silvery-white-to-grey powder, Silvery-white,

malleable, ductile, odorless metal.

Pb(NO3)2 – Lead(II) nitrate

Other names: Lead nitrate, Plumbous nitrate, Lead dinitrate

Appearance: White colorless crystals, White or colorless crystals

Products:

Al(NO3)3 – Aluminium nitrate

Other names: Nitric Aluminum salt, Aluminum nitrate,

Aluminium(III) nitrate

Appearance: White crystals, solid | hygroscopic

Pb - lead

Names: Lead, Lead metal, Plumbum

Appearance: Bluish-white or silvery-grey solid in various forms.

Turns tarnished on exposure to air. A heavy, ductile,

soft, gray solid.

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Given that a for HBrO is 2. 8×10^−9 at 25°C. What is the value of b for BrO− at 25°C?

lara [203]

If Ka for HBrO is 2. 8×10^−9 at 25°C, then the value of Kb for BrO− at 25°C is 3.5× 10^(-6).

<h3>What is base dissociation constant? </h3>

The base dissociation constant (Kb) is defined as the measurement of the ions which base can dissociate or dissolve in the aqueous solution. The greater the value of base dissociation constant greater will be its basicity an strength.

The dissociation reaction of hydrogen cyanide can be given as

HCN --- (H+) + (CN-)

Given,

The value of Ka for HCN is 2.8× 10^(-9)

The correlation between base dissociation constant and acid dissociation constant is

Kw = Ka × Kb

Kw = 10^(-14)

Substituting values of Ka and Kw,

Kb = 10^(-14) /{2.8×10^(-9) }

= 3.5× 10^(-6)

Thus, we find that if Ka for HBrO is 2. 8×10^−9 at 25°C, then the value of Kb for BrO− at 25°C is 3.5× 10^(-6).

DISCLAIMER: The above question have mistake. The correct question is given as

Question:

Given that Ka for HBrO is 2. 8×10^−9 at 25°C. What is the value of Kb for BrO− at 25°C?

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