What is the chemical name for the balanced equation? 2Al+3Pb(NO3)2=2Al(NO3)3+3Pb
1 answer:
- The chemical name for reactant side:
Al - Aluminium, Pb(NO3)2 - Lead(II) nitrate.
- The chemical name for product side:
Al(NO3)3 - Aluminium nitrate, Pb - lead.
<u>Explanation</u>:
- This is an oxidation-reduction (redox) reaction:
3 + 6 e- → 3
(reduction)
2 - 6 e- → 2
(oxidation)
Pb(NO3)2 is an oxidizing agent, Al is a reducing agent.
- Reactants:
Al uminium
Names: Aluminum, Aluminium powder, Al
Appearance: Silvery-white-to-grey powder, Silvery-white,
malleable, ductile, odorless metal.
Pb(NO3)2 – Lead(II) nitrate
Other names: Lead nitrate, Plumbous nitrate, Lead dinitrate
Appearance: White colorless crystals, White or colorless crystals
- Products:
Al(NO3)3 – Aluminium nitrate
Other names: Nitric Aluminum salt, Aluminum nitrate,
Aluminium(III) nitrate
Appearance: White crystals, solid | hygroscopic
Pb - lead
Names: Lead, Lead metal, Plumbum
Appearance: Bluish-white or silvery-grey solid in various forms.
Turns tarnished on exposure to air. A heavy, ductile,
soft, gray solid.
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Answer
b. 95%
Explanation
Given:
Mass of K₂O produced (actual yield) = 28.56 g
Mass of K that reacted = 25.00 g
Equation: 4K(s) + O₂(g) → 2K₂0(s)
What to find:
The percent yield of K₂O.
Step-by-step solution:
The first step is to calculate the theoretical yield of K₂O produced.
From the balanced equation, 4 mol K produced 2 mol K₂O
Molar mass of K₂O = 94.20 g/mol)
Molar mass of K = 39.10 g/mol)
This means 4 mol x 39.10 g/mol = 156.40 g K produced 2 mol x 94.20 g/mol = 188.40 g K₂O
So 25.00 g K will produce:
Actual yield of K₂O = 28.56 g
Theoretical yield of k₂O = 30.1151 g
The percent yield for the reaction can now be calculated using the formula below:
Therefore, the percent yield for the reaction is 95%.