NAD serves as the bulk of the oxidative processes in the citric acid cycle's initial electron acceptor.
<h3>What are
electron acceptors in c
itric acid cycle?</h3>
- In the Krebs cycle, which transfers electrons via the electron transport chain with oxygen as the final acceptor, coenzymes like FAD and NAD+ are reduced.
- In a single cycle, three NADH+ and one FADH2 are produced, and when the cycle enters the electron transport chain, 10 ATP is produced.
- The final electron acceptor in the electron transport chain is oxygen. The proton gradient in the intermembrane gap is produced by NADH molecules donating electrons that are then transmitted through a number of different proteins.
<h3>What occurs throughout the citric acid cycle?</h3>
The cycle of citric acid: In the citric acid cycle, a six-carbon citrate molecule is created when an acetyl group from acetyl CoA is joined to a four-carbon oxaloacetate molecule.
Citrate is oxidized over a number of steps, generating two molecules of carbon dioxide for each acetyl group added to the cycle.
learn more about citric acid cycle here
<u>brainly.com/question/14900762</u>
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Tighten the screw clamp over the fitting with a screwdriver, and place another metal screw clamp over the other end of the rubber vacuum line.
Answer:
Because Gay-LUssac's law works only on K scale. To find the answer you must convert C to K
Explanation:
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Answer:
C. 33.6L
Explanation:
Based on the reaction, 2 moles of HCl reacts producing 1 mole of hydrogen.
To solve this question we must find the moles of hydrogen produced using the reaction. Then, with combined gas law (PV = nRT) we can find the volume produced:
<em>Moles H2:</em>
3.00 moles HCl * (1mol H2 / 2mol HCl) = 1.50 moles H2 are produced
<em>Volume:</em>
PV = nRT
V = nRT / P
<em>Where P is pressure = 1atm at STP</em>
<em>V is volume = Our incognite</em>
<em>n are moles of the gas = 1.50 moles</em>
<em>R is gas constant = 0.082atmL/molK</em>
<em>T is absolute temperature = 273.15K</em>
<em />
V = nRT / P
V = 1.50mol*0.082atmL/molK*273.15K / 1atm
V = 33.6L
<h3>C. 33.6L</h3>
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