Answer:
Explanation:
Initial burette reading = 1.81 mL
final burette reading = 39.7 mL
volume of NaOH used = 39.7 - 1.81 = 37.89 mL .
37.89 mL of .1029 M NaOH is used to neutralise triprotic acid
No of moles contained by 37.89 mL of .1029 M NaOH
= .03789 x .1029 moles
= 3.89 x 10⁻³ moles
Since acid is triprotic , its equivalent weight = molecular weight / 3
No of moles of triprotic acid = 3.89 x 10⁻³ / 3
= 1.30 x 10⁻³ moles .
I think it's A, <span>an action which causes movement and an opposite reaction</span>
Answer:
It is better to do chemistry
Explanation:
So that you will learn more of chemicals
Answer:
The answers are as given in the attachment
Explanation:
The application of the de brogile equation was used and appropriate substitution were made as shown in the attachment
Option c. 6, -5, -1, 1/2
Because the second quantum number, l, cannot be negative.
The values of l are restricted to the range 0 to n -1, which in this case is 0, 1, 2, 3, 4 and 5.
