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Reil [10]
3 years ago
14

Calculate the mass of oxygen produced from the decomposition of 75.0 g of potassium chlorate?

Chemistry
2 answers:
Dmitry [639]3 years ago
4 0
The balanced reaction is:

<span>2KClO3 = 2KCl + 3O2

</span>

We are given the amount of potassium chlorate. This will be our starting point.

 

75.0 g KClO3 (1 mol KClO3 /122.55 g KClO3) (3 mol O2/2 mol <span>KClO3</span>) ( 32 g O2 / 1mol O2) = 58.75 g O2

 

Thus, the answer is 28.88g H2O.

Elis [28]3 years ago
4 0

Answer:

29.4 g

Explanation:

Let's consider the decomposition of potassium chlorate.

KClO₃ → KCl + 1.5 O₂

The molar mass of KClO₃ is 122.55 g/mol. The moles of KClO₃ in 75.0 g are:

75.0 g × (1 mol/ 122.55 g) = 0.612 mol

The molar ratio of KClO₃ to O₂ is 1:1.5. The moles of O₂ are 1.5 × 0.612 mol = 0.918 mol

The molar mass of O₂ is 32.00 g/mol. The mass of O₂ corresponding to 0.918 moles is:

0.918 mol × (32.00 g/mol) = 29.4 g

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At STP, 32 grams of O2 would occupy the same volume as:
ludmilkaskok [199]

At STP 32 g of O₂ would occupy by the same volume as  4 g of He

<h3>Further explanation</h3>

Complete question

At STP 32 g of O₂ would occupy by the same volume as:

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  • 8.0 g of CH₄
  • 64 g of H₂
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Standard Conditions

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters / mol.

So the gas will have the same volume if the number of moles is the same

mol of 32 grams of O₂ :

\tt \dfrac{32}{32}=1

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\tt mol=\dfrac{4}{4}=1

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\tt mol=\dfrac{8}{16}=0.5

  • H₂

\tt mol=\dfrac{64}{2}=32

  • SO₂

\tt mol=\dfrac{32}{64}=0.5

<em>So mol of 4 g He = mol of 32 g O₂</em>

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3 years ago
Helppppppppppppppppppppp
alukav5142 [94]

decameters - meters: multiply by 10

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centimeters to meters: divide by 100

millimeters to meters: divide by 1000

For the rows at the bottom:

hectometer row: 100, multiply by 100, 4500

decameter row: 10, multiply by 10, 450

meter row: 1, multiply by 1, 45

decimeter row: 0.1, divide by 10, 4.5

centimeter row: 0.01, divide by 100, 0.45

im guessing theres a millimeter row at the bottom:

millimeter row: 0.001, divide by 1000, 0.045


hope this helps!

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