Answer:
4 grams
Explanation:
A = A₀e^⁻kt
A₀ = 125.0 grams
k= 0.693/t(1/2) = (0.693/68.8) yrs⁻¹ = 0.01 yrs⁻¹
t = 344.0 years
A = 125.0g·[e^-(0.01yrs⁻¹)(344.0yrs)] = 125(0.032)grams = 4.000g (4 sog. figs. based on A₀ = 125.0 grams)
We have that the Complete Expanded Structure of (CH3)2CHCH2OCH2CH3 is given in the attachment below
From the Question
(CH3)2CHCH2OCH2CH3
Generally for the condensed formula (CH3)2CHCH2OCH2CH3
We consider that this is a single bond connecting them
We consider
Hydrogen H(1)
Oxygen(8)
Carbon(6)
In conclusion
The Complete Expanded Structure of (CH3)2CHCH2OCH2CH3 is given in the attachment below.
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brainly.com/question/24102840
External fertilization in animals usually occurs in water or in damp areas in a process called spawning.
Answer:
The water lost is 36% of the total mass of the hydrate
Explanation:
<u>Step 1:</u> Data given
Molar mass of CuSO4*5H2O = 250 g/mol
Molar mass of CuSO4 = 160 g/mol
<u>Step 2:</u> Calculate mass of water lost
Mass of water lost = 250 - 160 = 90 grams
<u>Step 3:</u> Calculate % water
% water = (mass water / total mass of hydrate)*100 %
% water = (90 grams / 250 grams )*100% = 36 %
We can control this by the following equation
The hydrate has 5 moles of H2O
5*18. = 90 grams
(90/250)*100% = 36%
(160/250)*100% = 64 %
The water lost is 36% of the total mass of the hydrate
