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7nadin3 [17]
3 years ago
6

A change in matter that produces one or more new substances is a(n)

Chemistry
1 answer:
lukranit [14]3 years ago
6 0

You could use another word for change can be variable witch means change and if you times the one two more times then you would get four because two time two would be four and times the one would be four.


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A 24.00 mL sample of a solution of Pb(ClO3)2 was diluted with water to 52.00 mL. A 17.00 mL sample of the dilute solution was fo
klio [65]

Answer:

0.238 M

Explanation:

A 17.00 mL sample of the dilute solution was found to contain 0.220 M ClO₃⁻(aq). The concentration is an intensive property, so the concentration in the 52.00 mL is also 0.220 M ClO₃⁻(aq). We can find the initial concentration of ClO₃⁻ using the dilution rule.

C₁.V₁ = C₂.V₂

C₁ × 24.00 mL = 0.220 M × 52.00 mL

C₁ = 0.477 M

The concentration of Pb(ClO₃)₂ is:

\frac{0.477molClO_{3}^{-} }{L} \times \frac{1molPb(ClO_{3})_{2}}{2molClO_{3}^{-}} =0.238M

4 0
3 years ago
Write Huckel's rule below and determine how many electrons are required to make an aromatic ring with n = 0, 1, and 2.
lisov135 [29]

<u>Answer:</u> The number of electrons for n = 0, 1 and 2 are 2, 6 and 10 respectively.

<u>Explanation:</u>

Huckel's rule is used to determine the aromaticity in a compound. The number of delocalized \pi- electrons are calculated by using the equation:

\text{Number of delocalized }\pi-\text{ electrons}=4n+2

where,

n = 0 or any whole number

  • Calculating the value of electrons for n = 0

Putting values in above equation, we get:

\text{Number of delocalized }\pi-\text{ electrons}=4(0)+2=2

  • Calculating the value of electrons for n = 1

Putting values in above equation, we get:

\text{Number of delocalized }\pi-\text{ electrons}=4(1)+2=6

  • Calculating the value of electrons for n = 2

Putting values in above equation, we get:

\text{Number of delocalized }\pi-\text{ electrons}=4(2)+2=10

Hence, the number of electrons for n = 0, 1 and 2 are 2, 6 and 10 respectively.

4 0
3 years ago
Complexes containing metals with d10 electron configurations are typically colorless because ________. Complexes containing meta
algol [13]

Answer:

there is no d electron that can be promoted via the absorption of visible light

Explanation:

One of the properties of transition elements is the possession of incompletely filled d orbitals. This property accounts for their unique colours.

The colours of transition metal compounds stem from d-d transition of electrons due to the presence of vacant d orbitals of appropriate energy to which electrons could be promoted.

For elements whose atoms have a d10 configuration, such vacant orbitals does not exist hence their compounds are not colored.

Sometimes, the colour of transition metal compounds stem from ligand to metal charge transfer(LMCT) for instance in KMnO4.

8 0
2 years ago
True or False? <br><br> A day is about 12 hours long
7nadin3 [17]

Answer:

false it's 24 hours long.

7 0
2 years ago
Why do solids exist ?
lubasha [3.4K]

Answer:

A solid's particles are packed closely together. The forces between the particles are strong enough that the particles cannot move freely; they can only vibrate. As a result, a solid has a stable, definite shape and a definite volume. Solids can only change shape under force, as when broken or cut.

7 0
2 years ago
Read 2 more answers
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