The sample of smoke described above can be described as a heterogeneous mixture. This type of mixture do not have uniform properties and composition. So, getting a certain small sample would not represent the whole mixture since it does not have uniform composition.
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The moles which were measured out is calculated using the following formula
moles = mass/molar mass
molar mass of CuBr2.4H20 = 63.5 Cu + ( 2 x79.9) br + ( 18 x4_) h20 = 295.3 g/mol
moles is therefore= 5.2 g/ 295.3 g/mol= 0.0176 moles
Answer:
20.0/1 x 1mole/58.44=0.34
(Atomic mass of salt)
Been a minute since I've done this, but this is how I remember doing it, soo..hope this helps!
First you must write a balanced chemical equation.
C3H8 + 5O2 --> 3CO2 + 4H2O
From there, we can set up the stoichiometry equation to solve.
g O2= 70.2 g C3H8 X (1 mol C3H8/44.0962g C3H8) X (5 mol O2/1 mol C3H8) X (31.998g O2/1 mol O2)
Now solve, and you should get 254.7 g O2. Hope this helped!
