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olga nikolaevna [1]
3 years ago
7

A ball is thrown vertically upwards at an initial speed of

Physics
1 answer:
sveta [45]3 years ago
6 0

Answer:

114m

Explanation:

s=ut + 1/2 at^2

s=23 m/s ×3s + 1/2×3×3s^2×10m/s^2

= (69+45)m

= 114m

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Use this media to help you complete the question.
Papessa [141]

Answer:

589.3 g is the answer

Explanation:

6 0
3 years ago
Problem 4: A mass m = 1.5 kg hangs at the end of a vertical spring whose top end is fixed to the ceiling. The spring has spring
lana [24]

Answer:

y (t) = 0.754 * cos ( 7.96 t - 69.52)

Explanation:

Given:

m = 1.5 kg , k = 95 N / m , v₀ = 6 m / s , d = 0.35 m , t = 0

y (t) = A * cos ( ω * t - φ )

Using the equation that describe the motion

m * v = - k * x  ⇒ m * x'' = - k * x

Angular velocity is equal to

ω = √ k / m   ⇒ ω = √ 95 N /m  /  1.5 kg  

ω = 7.96  rad /s

A = v / ω   ⇒  A = 6 m /s   /   7.96 rad / s

A = 0.754

d = cos * φ    ⇒  φ = cos ⁻¹ * 0.35

φ = 69.52

y (t) = A * cos ( ω * t - φ )    ⇒  y (t) = 0.754 * cos ( 7.96 t - 69.52)

4 0
3 years ago
When is the angular momentum of a system constant?
Artist 52 [7]
I think it’s a but I’m not 100% sure
4 0
3 years ago
2. A ball is tossed straight upwards with a velocity of 60m/s. Using an estimate of gravity of -10m/s², about how many seconds w
sdas [7]

Answer: A

Explanation:

4 0
2 years ago
A 0.300 kg potato is tied to a string with length 2.30 m , and the other end of the string is tied to a rigid support. The potat
alexdok [17]

Answer:

The speed of the potato at the lowest point is 6.714 m/s

The tension in the string is 8.82 N

Explanation:

We will use law of conservation of energy to find out the velocity

When the potato is at 2.30 m height, it will have potential energy and when  the potato released it will go lowest point and it's potential energy will be convert into kinetic energy.

                       Potential energy = Kinetic energy

                                  m×g×h      = (1/2) m×v²

m stands  for mass

g stands for gravitational constant

h stands for height

v stands for velocity

                      m×g×h      = (1/2) m×v²

                      0.3×9.8×2.3 = (1/2) .3×v²

                       v² = 45.08

                       v  = 6.714 m/s

The speed of the potato at lowest point is 6.714 m/s

Part B

 The potato is in uniform circular motion so the acceleration is given by

                          a = v² / r

a stands for centripetal acceleration

According to Newton second law the acceleration  is  directly proportional to applied force and inversely proportional to the mass of object

     So                     ∑ F = m × a

Two forces act on potato 1. weight due to gravitation in downward direction 2. tension in upward direction So the above equation become

                     Tension force - Force due to weight = m×a

                     T-m×g     = m×a

           centripetal acceleration formula =v²/r    ,   r = l = length of the string

                        T  = m ×(v²/l) + m×g

  v = 6.714 m/s ,  l = 2.30 m ,   m = .3 kg Now put values in above equation

                         T = .3 × (6.714²/2.30) + .3 × 9.8

                        T  = .3 ( 45.08/2.30) + 2.94

                        T  = .3 (19.6) +2.94

                        T  = 5.88 + 2.94

                        T  = 8.82 N

          The tension in the string is 8.82 N

5 0
3 years ago
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