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lions [1.4K]
3 years ago
7

1. What kind of reward do you want most from your friendships? Do you look for excitement, closeness, acceptance, or something e

lse? Describe in three complete sentences.
2. What's a positive way that you can get the reward you chose in the first question? Describe in two complete sentences.
Physics
1 answer:
charle [14.2K]3 years ago
3 0

Answer: It is our need for company that urges us to make friends. So we make friends for companionship.

<u>Explanation:</u>

The kind of reward that we want from friendship is companionship.

  1. We make friends for a company. It is our need for a company that urges us to make friends.
  2. We enjoy when we have a friend. Life becomes relaxed.
  3. Our friend is our companion so we can easily share our problems with him or her.

The positive way that we can get this reward of companionship is

  1. Man is a social animal. He needs a company to live, otherwise, he cannot survive. So companionship satisfies our social needs.
  2. Human beings are emotional too. They need to share their feelings. So they can share it with their companion. We are emotionally satisfied.

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The man is standing on the plank. Then he is pulling the rope towards himself. He pushes the plank forward with the legs so that he can pull the rope backwards.

The man is standing on the plank. Then he is pulling the rope towards himself. He pushes the plank forward with the legs so that he can pull the rope backwards. So the friction f acts in the forward direction for the plank. Also f acts in the opposite direction on the man. The tension T in the rope is 100 N (given). Let the friction force = f Newtons.

The man is standing on the plank. Then he is pulling the rope towards himself. He pushes the plank forward with the legs so that he can pull the rope backwards. So the friction f acts in the forward direction for the plank. Also f acts in the opposite direction on the man. The tension T in the rope is 100 N (given). Let the friction force = f Newtons.Let the common acceleration = a m/s^2

Man: <em>net force = T - f = m a = 50 a </em>

<em>net force = T - f = m a = 50 a </em>

<em>Plank: net force = T + f = m a = 100 a</em>

<em>net force = T - f = m a = 50 a </em>

<em>Plank: net force = T + f = m a = 100 a</em>

<em>As T = 100 N, a = 4/3 m/s^2 and f = 100/3 Newtons. </em>

[correct me if I'm wrong]:)

6 0
3 years ago
Read 2 more answers
A disk-shaped platform has a known rotational inertia. The platform is mounted on a fixed axle and rotates in a horizontal plane
Nataly [62]

The frictional torque exerted on the platform by the axle as the platform rotates will be;

\rm T_f \theta =\frac{1}{2} I [\omega^2-\omega_0^2]

<h3>What is torque?</h3>

Torque is the force's twisting action about the axis of rotation. Torque is the term used to describe the instant of force. It is the rotational equivalent of force. Torque is a force that acts in a turn or twist.

The amount of torque is equal to force multiplied by the perpendicular distance between the point of application of force and the axis of rotation.

Work done by the frictional torque = Change in the rotational kinetic energy of the wheel

\rm T_f \theta =\frac{1}{2} I [\omega^2-\omega_0^2]

Where,

\rm T_f is the frictional torque

\rm \omega is the final angular velocity

\rm  \omega_0 is the initial angular velocity

\rm \theta is the angular displacement

Hence, the frictional torque exerted on the platform by the axle as the platform rotates will be;

\rm T_f \theta =\frac{1}{2} I [\omega^2-\omega_0^2]

To learn more about the torque, refer to the link;

brainly.com/question/6855614

#SPJ1

5 0
2 years ago
A 0.877 mol sample of N2(g) initially at 298 K and 1.00 atm is held at constant volume while enough heat is applied to raise the
MissTica

Answer : The value of q\text{ and }\Delta U is 286.2 J and 286.2 J respectively.

Explanation : Given,

Moles of sample = 0.877 mol

Change in temperature = 15.7 K

First we have to calculate the heat absorbed by the system.

Formula used :

q=n\times c_v\times \Delta T

where,

q = heat absorbed by the system = ?

n = moles of sample = 0.877 mol

\Delta T = Change in temperature = 15.7 K

c_v = heat capacity at constant volume of N_2 (diatomic molecule) = \frac{5}{2}R

R = gas constant = 8.314 J/mol.K

Now put all the given value in the above formula, we get:

q=0.877mol\times \frac{5}{2}\times 8.314J/mol.K\times 15.7K

q=286.2J

Now we have to calculate the change in internal energy of the system.

\Delta U=q+w

As we know that, work done is zero at constant volume. So,

\Delta U=q=286.2J

Therefore, the value of q\text{ and }\Delta U is 286.2 J and 286.2 J respectively.

8 0
4 years ago
Read 2 more answers
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