Which of the following would experience induced magnetism mosteasily?

Mrs. Waid drives her car up Route 8 at 80mph. If her car weighs 2500 lbs,

Anvisha [2.4K]

1.358 J is the kinetic energy of the car driven by Mrs. Waid.

<u>Explanation:</u>

Given data:

Velocity at which Mrs. Waid drives her car = 80 mph

In order to convert mph (meter per hour) into mps (meter per second),

$\frac{80}{3600}=0.0222 \mathrm{m} / \mathrm{s}$

Car weighs 2500 lbs, means mass of the car, m = 2500 lbs

I kilo gram = 2.20462 pound

Therefore, 1 pound (lb)= 0.45359237 kilograms (kg).

To converting pounds into kilogram,

$\frac{2500}{0.45359237}=5511.55 \mathrm{kg}$

As we know, the kinetic energy can be defined as directly proportionate to the object’s mass (m) and square of its velocity (v). The expression can be given as below,

$\text { kinetic energy }(K . E)=\frac{1}{2} \times m \times v^{2}$

By substituting the given values, we get

$\text { kinetic energy }(K . E)=\frac{1}{2} \times 5511.55 \times 0.0222^{2}$

$\text { kinetic energy }(K . E)=\frac{1}{2} \times 5511.55 \times 0.00049$

$kinetic energy (K . E)=1.358 joule$

3 0

4 years ago

20 POINTSSS!!!!!!!!

Soloha48 [4]

Answer: A
Hope this help you!!

7 0

3 years ago

This 200-kg horse ran the track at a speed of 5 m/s. What was the average kinetic energy?

MrRissso [65]

Answer:

Explanation:

The average kinetic energy can be found by using the formula

$k = \frac{1}{2} m {v}^{2} \\$

m is the mass

v is the velocity

From the question we have

$k = \frac{1}{2} \times 200 \times {5}^{2} \\ = 100 \times 25$

We have the final answer is

Hope this helps you

5 0

3 years ago

Calculate the normal force pushing up from the table in each example 8 kg

garik1379 [7]

The correct answer to the question is: 78.4 N.

EXPLANATION:

As per the question, the mass of the object is given as m = 8 Kg.

We are asked to calculate the normal force of the object.

The object is resting on the table.

Hence, the object pushes the table downward with a force equal to it's weight.

The table, in turn, pushes the object with the same force as given by the object, but in the upward direction.

The force given by the table on the object is known as the normal reaction of the object which acts perpendicular to the surface of the object.

Hence, the normal reaction is equal to the weight of the body.

The weight of a body is the product of it's mass with acceleration due to gravity.

So, the weight of 8 Kg object is calculated as -

Weight = mg

= 8 × 9.8 N.

= 78.4 N.

Here, g is known as acceleration due to gravity.

Hence, the normal force pushing up from the table is 78.4 N.

8 0

3 years ago

If the Hubble Space Telescope is 598 m above the surface of the Earth and is traveling at 7.56 x 103 m/s, how long does it take

viva [34]

Answer:

5069.04 seconds

Explanation:

The parameter we are looking for is called the Orbital period of the Hubble Space Telescope.

It is given as:

$T = \sqrt{\frac{4\pi^2r^3 }{GM} }$

where r = radius of orbit of Hubble Space Telescope

G = gravitational constant = $6.67408 * 10^{-11} m^3 kg^{-1} s^{-2}$

M = Mass of earth

We are given that:

r = radius of the earth + distance of HST from earth

r = $6.38 * 10^6 + 598 = 6380598 m$

M = $5.98 * 10^{24} kg$

Therefore, T will be:

$T = \sqrt{\frac{4*\pi^2 * 6380598^3 }{6.67408 * 10^{-11} * 5.98 * 10^{24}}}$

$T = 5069.04 secs$

The orbital period of the Hubble Space Telescope is 5069.04 seconds.

7 0

3 years ago

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