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AlekseyPX
2 years ago
10

Convert 7.1X1025 molecules of water to moles

Chemistry
1 answer:
scoundrel [369]2 years ago
5 0

Answer:

Moles of water in 7.1×10²⁵ molecules are 118 mol.

Explanation:

Given data:

Number of molecules of water = 7.1×10²⁵ molecules

Moles of water in 7.1×10²⁵ molecules = ?

Solution;

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

1 mole = 6.022 × 10²³ molecules of water

7.1×10²⁵ molecules of water × 1 mol / 6.022 × 10²³ molecules of water

1.18×10² moles of water 0r 118 moles of water

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Chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid, HCl(aq)HCl(aq) , as desc
vlada-n [284]

Answer:

0.87g

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

MnO2(s) + 4HCl(aq) —> MnCl2(aq) + 2H2O(l) + Cl2(g)

Step 2:

Data obtained from the question. This includes the following:

Volume (V) of Cl2 obtained = 235mL

Temperature (T) = 25°C

Pressure (P) = 805 Torr

Step 3:

Conversion to appropriate unit.

For Volume:

1000mL = 1L

Therefore, 235mL = 235/1000 = 0.235L

For temperature:

Temperature (Kelvin) = temperature (celsius) + 273

Temperature (celsius) = 25°C

Temperature (Kelvin) = 25°C + 273 = 298K

For Pressure:

760 Torr = 1 atm

Therefore, 805 Torr = 805/760 = 1.06 atm

Step 4:

Determination of the number of mole of Cl2 produced. This is illustrated below:

The number of mole (n) of Cl2 produced can be obtained by using the ideal gas equation as follow:

PV = nRT

Volume (V) = 0.235L

Temperature (T) = 298k

Pressure (P) = 1.06 atm

Gas constant (R) = 0.082atm.L/Kmol

Number of mole (n)

PV = nRT

Divide both side by RT

n = PV /RT

n = (1.06 x 0.235)/(0.082 x 298)

n = 0.01 mole

Therefore 0.01 mole of Cl2 is produced from the reaction.

Step 5:

Determination of the number of mole MnO2 that produce 0.01 mole of Cl2. This is illustrated below:

MnO2(s) + 4HCl(aq) —> MnCl2(aq) + 2H2O(l) + Cl2(g)

From the balanced equation above,

1 mole of MnO2 produced 1 mole of Cl2.

Therefore, it will take 0.01 mole to MnO2 to also produce 0.01 mole of Cl2.

Step 6:

Converting 0.01 mole of MnO2 to grams.

This is illustrated below:

Number of mole MnO2 = 0.01 mole

Molar Mass of MnO2 = 55 + (2x16) = 87g/mol

Mass of MnO2 =?

Mass = number of mole x molar Mass

Mass of MnO2 = 0.01 x 87

Mass of MnO2 = 0.87g

Therefore, 0.87g of MnO2 is needed for the reaction.

8 0
3 years ago
Frequency of 6.98 x 1013
MAVERICK [17]

Answer:7,070.74

Explanation:because frequency has a lot of energy

6 0
2 years ago
How many centimeters are in .479 kilometers
trapecia [35]

Answer:

47900 cm

General Formulas and Concepts:

<u>Chemistry</u>

  • Base 10 Decimal System
  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

0.479 km

<u>Step 2: Identify Conversions</u>

1 km = 1000 m

1 m = 100 cm

<u>Step 3: Convert</u>

<u />0.479 \ km(\frac{1000 \ m}{1 \ km} )(\frac{100 \ cm}{1 \ m} ) = 47900. cm

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules.</em>

47900. cm ≈ 47900 cm

7 0
3 years ago
Sam investigates the reactivity of metals in air. His observations are shown below.
viva [34]

Answer:5

Explanation:

6 0
2 years ago
Read 2 more answers
Pleasee help <br> will name brainliest
zmey [24]

Answer:

0.125. work- divide the volume value by 1000

873. work- multiply the length value by 100

98100. work- Conversion factor: 1 kg = 100000 cg

1) Centigram = Kilogram * 100000

2) Centigram = 0.981 * 100000

3) Centigram = 98100

285.65. work- 12.5°C + 273.15 = 285.65K

446.85. work- 720K − 273.15 = 446.85°C

346.25. work- 73.1°C + 273.15 = 346.25K

Explanation:

i hope this helps:)  brainliest plss??

8 0
3 years ago
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