2H₂₍g₎ + O₂ ₍g₎→ 2H₂O
138 mol H₂ × (2 mol H₂O ÷ 2 mol H₂)= 138 mol H₂O
64 mol O₂ × (2 mol H₂O ÷ 1 mol O₂)= 128 mol H₂O
128 mol H₂O
mass (m) = ? , volume = 18.0 ml , density = 1.42 g/ml .

I hope I helped you^_^
Answer:
The value of the equilibrium constant for the reaction A ⇒ B is Kc = 1.72 × 10³.
The value of the equilibrium constant for the reaction B ⇒ A is K'c = 5.81 × 10⁻⁴.
Explanation:
For the reaction A ⇒ B, the equilibrium constant (Kc) is equal to the forward rate constant (kf) divided by the reverse rate constant (ki).

If we consider the inverse reaction B ⇒ A, its equilibrium constant (K'c) is the inverse of the forward reaction equilibrium constant.

Answer:
4-wheeler
Explanation:
I was thinking that you could say this:
My design is that the 4-wheeler will detect, with the help of technology, when something is approaching or you are very close to it. As the object gets closer, it will beep faster and louder. When the 4-wheeler beeps really fast and really loud, it means that you are about to crash or you are in danger. It will stop and launch an airbag so you stay safe. When the 4-wheeler stops, it will make a signal to let people know that you have stopped.
I am so sorry if this wasn't the response that you were looking for.
Hope this helped!
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