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Lostsunrise [7]
3 years ago
13

How do you answer this chem equation: 836.8J=14.5g*Cm*64

Chemistry
1 answer:
Alja [10]3 years ago
8 0
Is that a thing? Maybe you've said it wrong. Otherwise, I don't think you don't learn this in middle school.

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What is the formula of the hydride formed by germanium?
Nadusha1986 [10]

The atoms combine to form compounds to attain stability in nature. The combination of atoms takes place by sharing of electrons between the atoms or complete transfer of electrons from one atom to another. Generally, atoms combine to complete their octet, that is to possess eight electrons in their outer most shell (noble gas configurations) except hydrogen which can attain stability by two electrons in its outer most shell.

Since germanium has 4 electrons in its outer most shell so it needs 4 more electrons to complete its octet and attains the stability. Hydrogen has 1 electron in its outer most shell and it needs only 1 electron to attain stability so, each germanium will combine with 4 hydrogen atoms and thus forming GeH_4 molecule which is stable in nature.

Hence, GeH_4 is the formula of the hydride formed by germanium.


6 0
3 years ago
2Na(s) + 2H,O(l) — 2NaOH(?) + H, (g)<br> 0 what is the missing symbol
Klio2033 [76]

Answer:

the symbol that is missing might be 2.

Explanation:

I am not 100% on this, so correct me if I am wrong.

3 0
2 years ago
Help I don’t understand it and I need the answers
il63 [147K]

Answer:

Demonstration 1 showed a chemical change because a new gaseous substance was formed, and demonstration 2 showed a physical change because liquid water became water vapor.

Explanation:

Chemical changes alter the chemical makeup of a subject, and a physical change only alters the appearance of a subject, not the chemical makeup.

4 0
3 years ago
Erbium (Er) is element 68 on the periodic table. A sample contains 5.04×1023 atoms of Er. Calculate the amount of Er.
Korvikt [17]

Answer:

139.98 g to nearest hundredth.

Explanation:

Using Avogadro's Number:

One mole (167.26 g) of Erbium  equates to  6.022141 * 10^23 atoms.

So 5.04 * 10^23 = 167.26 * 5.04/6.022141

= 139,98 g.

3 0
3 years ago
A sample of an unidentified compound contains 29.84% sodium, 67.49% chromium, and 72.67% oxygen. What is the compound's empirica
vladimir1956 [14]

Answer:

i would help i just dont know sorry

Explanation:

5 0
3 years ago
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