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3 years ago

Please help meee with this question

Chemistry

2 answers:

tiny-mole [99]3 years ago

5 0

Osmosis is the diffusion of water from a high concentration to a lower concentration

matrenka [14]3 years ago

3 0

Osmosis is the diffusion of water from a high concentration to a lower concentration

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Help please chapter 7.1

olga2289 [7]

1. 100N to the right
2. 10N to the left
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4. 0N they are balanced

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3 years ago

Given : 4.50 molte

Lelu [443]

You would get 35.................

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2 years ago

A moist red litmus paper is used for testing ammonia gas ,why

yawa3891 [41]

Answer:

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3 years ago

A hypothetical element has an atomic weight of 48.68 amu. It consists of three isotopes having masses of 47.00 amu, 48.00 amu, a

Morgarella [4.7K]

Answer : The percent abundance of the heaviest isotope is, 78 %

Explanation :

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$

As we are given that,

Average atomic mass = 48.68 amu

Mass of heaviest-weight isotope = 49.00 amu

Let the percentage abundance of heaviest-weight isotope = x %

Fractional abundance of heaviest-weight isotope = $\frac{x}{100}$

Mass of lightest-weight isotope = 47.00 amu

Percentage abundance of lightest-weight isotope = 10 %

Fractional abundance of lightest-weight isotope = $\frac{10}{100}$

Mass of middle-weight isotope = 48.00 amu

Percentage abundance of middle-weight isotope = [100 - (x + 10)] % = (90 - x) %

Fractional abundance of middle-weight isotope = $\frac{(90-x)}{100}$

Now put all the given values in above formula, we get:

$48.68=[(47.0\times \frac{10}{100})+(48.0\times \frac{(90-x)}{100})+(49.0\times \frac{x}{100})]$

$x=78\%$

Therefore, the percent abundance of the heaviest isotope is, 78 %

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3 years ago

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Glacier and erosion in a sentence

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