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saw5 [17]
3 years ago
7

Molly runs each morning once around a circular path in her neighborhood. if the diameter of the path is 1.4 miles, how far does

molly run each day?
Mathematics
1 answer:
Lemur [1.5K]3 years ago
6 0
To work out the distance of the path, you need to find out the circumference.
Formula for circumference = pi multiplied by the diameter

So you simply do:
pi multiplied by 1.4 miles

And you should get:
4.39822971503... miles

Simply round the result to an appropriate value (e.g. 3 decimal places).

Answer: 4.398 miles (to 3dp)
Hope the answer helps :)
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FInd an equation of the line that passes through the point (3,-5) and is parallel to 4x=1+2y
kow [346]

Answer:

y=2x-11

Step-by-step explanation:

Put it in the form y=mx+b=>y=2x-1/2. Instead of -1/2, put it as b, since you want it to go through 3,-5. y=2m+b when it goes through (3,-5) happens when -5=3*2-b. Do algebra, and get b as 11. That means the equation is y=2x-11.

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Find all numbers whose absolute value is 2 .
Amiraneli [1.4K]
Absolute value of a real number, is the distance between that number and 0 on a number line. Therefore the absolute value of 2 is 2 and negative 2
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3 years ago
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Rationalize the denominator of sqrt -49 over (7 - 2i) - (4 + 9i)
zubka84 [21]
\sqrt{ \frac{-49}{(7-2i)-(4+9i) } } 


This one is quite the deal, but we can begin by distributing the negative on the denominator and getting rid of the parenthesis:

\frac{ \sqrt{-49}}{7-2i-4-9i}

See how the denominator now is more a simplification of like terms, with this I mean that you operate the numbers with an "i" together and the ones that do not have an "i" together as well. Namely, the 7 and the -4, the -2i with the -9i.
Therefore having the result: 

\frac{ \sqrt{-49} }{3-11i}

Now, the \sqrt{-49} must be respresented as an imaginary number, and using the multiplication of radicals, we can simplify it to \sqrt{49}  \sqrt{-1}
This means that we get the result 7i for the numerator.

\frac{7i}{3-11i}

In order to rationalize this fraction even further, we have to remember an identity from the previous algebra classes, namely: x^2 - y^2 =(x+y)(x-y)
The difference of squares allows us to remove the imaginary part of this fraction, leaving us with a real number, hopefully, on the denominator.

\frac{7i (3+11i)}{(3-11i)(3+11i)}

See, all I did there was multiply both numerator and denominator with (3+11i) so I could complete the difference of squares.
See how (3-11i)(3+11i)= 3^2 -(11i)^2 therefore, we can finally write:

\frac{7i(3+11i)}{3^2 - (11i)^2 }

I'll let you take it from here, all you have to do is simplify it further.
The simplification is quite straightforward, the numerator distributed the 7i. Namely the product 7i(3+11i) = 21i+77i^2.
You should know from your classes that i^2 = -1, thefore the numerator simplifies to -77+21i
You can do it as a curious thing, but simplifying yields the result:
\frac{-77+21i}{130}
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3 years ago
What is the Difference Between a 16-Ounce Brick and a Carpenter?
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One weighs a pound, and the other pounds away!

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Answer:

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Step-by-step explanation:

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