It’s (-8z^2 +8x +4y -2z)
Hope it helps
Hello from MrBillDoesMath!
Answer:
x = 2 and 10
Discussion:
Approach 1:
20 = (-10)*(-2) and (-10) + (-2) = -12 the coefficients of the polynomial. Hence
x^2 -12x + 20 = ( x- 2) * ( x-10)
Approach 2:
From the quadratic formula ( a = 1, b = -12, c = 20)
x = ( -(-12) +\- sqrt( ((-12)^2 - 4*1*20) ) / (2 * 1)
= ( 12 +\- sqrt( 144-80) ) /2
= (12 +\- sqrt(64) ) /2
= (12 +\- 8 ) /2
x = ( 12 + 8) /2 = 20/2 = 10
or
x = ( 12 - 8)/ 2 = 4/2 = 2
Thank you,
MrB
Y2-y1 / x2-x1 i think. not sure if that's correct
Answer:
I'm not 100% sure but I believe the answer is 27
because -48/-4=12
12+15=27
Answer:
Step-by-step explanation:
AD and EH are parallel lines
Angle CBD = Angle CFH = x (corresponding angles)
x + 2x = 180 (angles on a straight line)
3x = 180
x = 60
Angle GFH = 120
Angle CBD = 60
