Question

If f(3) = 2 and f'(3) = -4 , find an equation of the tangent line when x = 3.

Answer 1

Answer:

B

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

f'(3) = - 4 ← is the slope of the line at x = 3

and f(3) = 2 is the point (3, 2 ) thus

y - 2 = - 4(x - 3) ← add 2 to both sides

y = - 4(x - 3) + 2 → B