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maw [93]
3 years ago
5

The cost to mail a letter is a base charge of $0.42 plus $0.17 for each ounce. Write an equation that could be used to find how

many ounces a letter that costs $0.93 weighs. (Let x represent the number of ounces.)
0.59x = 0.93 0.42x + 0.17 = 0.93 0.59 = 0.93x 0.42 + 0.17x = 0.93
Mathematics
2 answers:
morpeh [17]3 years ago
6 0
Equation: 0.93 = 0.42 + 17x
marissa [1.9K]3 years ago
3 0

Answer:

0.42x + 0.17 = 0.93

I have already done this

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Solve the system of equations<br> -6y+11x=-36 <br> -4y+7x=-24 <br> x=<br> y=
Papessa [141]

Answer:

Y=6

X=0

Step-by-step explanation:

Hope this helps

3 0
3 years ago
Match the following rational expressions to their rewritten forms.
Nookie1986 [14]

Answer:

Answer image is attached.

Step-by-step explanation:

Given rational expressions:

1.\ \dfrac{x^2+x+4}{x-2}\\2.\ \dfrac{x^2-x+4}{x-2}\\3.\ \dfrac{x^2-4x+10}{x-2}\\4.\ \dfrac{x^2-5x+16}{x-2}

And the rewritten forms:

(x-2)+\dfrac{6}{x-2}\\(x+3)+\dfrac{10}{x-2}\\(x+1)+\dfrac{6}{x-2}\\(x-3)+\dfrac{10}{x-2}

We have to match the rewritten terms with the given expressions.

Let us consider the rewritten terms and let us solve them one by one by taking LCM.

(x-2)+\dfrac{6}{x-2}\\\Rightarrow \dfrac{(x-2)^{2}+6 }{x-2}\\\Rightarrow \dfrac{x^2-4x+4+6 }{x-2}\\\Rightarrow \dfrac{x^2-4x+10}{x-2}

So, correct option is 3.

(x+3)+\dfrac{10}{x-2}\\\Rightarrow \dfrac{(x+3)(x-2)+10}{x-2}\\\Rightarrow \dfrac{(x^2+3x-2x-6)+10}{x-2}\\\Rightarrow \dfrac{x^2+x+4}{x-2}

So, correct option is 1.

(x+1)+\dfrac{6}{x-2}\\\Rightarrow \dfrac{(x+1)(x-2)+6}{x-2}\\\Rightarrow \dfrac{x^{2} +x-2x-2+6}{x-2}\\\Rightarrow \dfrac{x^{2} -x+4}{x-2}

So, correct option is 2.

(x-3)+\dfrac{10}{x-2}\\\Rightarrow \dfrac{(x-3)(x-2)+10}{x-2}\\\Rightarrow \dfrac{x^2-3x-2x+6+10}{x-2}\\\Rightarrow \dfrac{x^2-5x+16}{x-2}

So, correct option is 4.

The answer is also attached in the answer area.

7 0
3 years ago
) Lucy, Soling, Kyan, and Daniel are ordering dinner for their families. Each person spends
melisa1 [442]

Answer:

Lucy is 5(m+3)=65

Soling is 5m-3=65

Kyan is 5m+3=65

Daniel is 5(m-3)=65

Step-by-step explanation:

3 0
3 years ago
The Carousel at Carowinds has 4 rings of horses. Fred is riding on the inner ring, which has a radius of 7 feet. Juan is riding
nikdorinn [45]

Answer:

Juan travel 31.4 feet farther than Fred in one rotation.

Step-by-step explanation:

In this problem we need to determine the change in linear position of Fred and Juan, whose formula is:

s=\theta \cdot r (Eq. 1)

Where:

r - Radius, measured in feet.

\theta - Angular arch, measured in radians.

s - Change in linear position, measured in feet.

If both makes one rotation in the carousel, we obtain the change in linear position of each player:

Fred (r = 7\,ft, \theta = 2\pi)

s= 2\pi\cdot (7\,ft)

s = (3.14)\cdot (7\,ft)

s = 21.98\,ft

Juan (r = 17\,ft, \theta = 2\pi)

s= 2\pi\cdot (17\,ft)

s = (3.14)\cdot (17\,ft)

s = 53.38\,ft

And the difference between both travelled distances is:

\Delta s = 53.38\,ft-21.98\,ft

\Delta s = 31.4\,ft

Juan travel 31.4 feet farther than Fred in one rotation.

4 0
3 years ago
I need help with Geometry. If you can help comment and I will message you.
Semmy [17]
I'll give it a go :) 
7 0
3 years ago
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