Answer:
Newton's second law says that F=ma, so if the force applied is zero, then the acceleration must also be zero.
Explanation:
Let's set the equation to 0 = ma. If mass is a nonzero value, then the acceleration must be zero to solve the equation. Therefore, if the force applied to an object is zero, then it will not accelerate (i.e. change speed or direction).
<span>It's another energy balance equation, though: energy to start with is the same as energy that you end with. Suppose that we start a distance r0 from the Earth and end a distance r1 from the Moon, then the energy balance gives:
1 v02 - G M / r0 - G m / (D - r0) = 1 v12 - G M / (D - r1) - G m / r1
...where m is the moon's mass.
One simple limit takes D ? ? and 1 v02 ? G M / r0 (the escape velocity equation), to yield:
1 v12 ? G M / r1
v1 ? ?( 2 G M / r1 ) = 2377 m/s.</span>
That's a formula that shows the relationship between three quantities ...
weight, mass, and acceleration. If you know any two of them, then you
can use this formula to find the one you don't know.
Examples:
==> I have a rock with 2 kilograms of mass.
The gravitational acceleration on Earth is 9.8 m/s² .
How much does my rock weigh on Earth ?
Weight = (mass) x (grav acceleration)
= (2 kg) x (9.8 m/s²)
= 19.6 newtons
(about 4.41 pounds)
==> My brother weighs 770 newtons (about 173 pounds) on Earth.
What is his mass ?
Weight = (mass) x (grav acceleration)
770 newtons = (mass) x (9.8 m/s²)
Divide each side
by 9.8 m/s²: 770 newtons / 9.8 m/s² = mass
78.57 kilograms = mass
==> When I went to the Moon, I took along my 2-kilogram rock.
I weighed my rock on the Moon.
It weighs 3.25 newtons (about 0.73 pound) there.
What is the gravitational acceleration on the Moon ?
Weight = (mass) x (grav acceleration)
3.25 newtons = (2 kg) x (acceleration)
Divide each side
by 2 kilograms: (3.25 newtons)/(2 kg) = acceleration
1.63 m/s² = grav acceleration on the Moon
Answer:
The young tree, originally bent, has been brought into the vertical position by adjusting the three guy-wire tensions to AB = 7 lb, AC = 8 lb, and AD = 10 lb. Determine the force and moment reactions at the trunk base point O. Neglect the weight of the tree.
C and D are 3.1' from the y axis B and C are 5.4' away from the x axis and A has a height of 5.2'
Explanation:
See attached picture.
Answer:
- Increase the concentration of the reactants
-increase the temperature
- introduce a catalyst
