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andreyandreev [35.5K]
3 years ago
6

Use the given information to prove that BC=DE

Mathematics
1 answer:
lions [1.4K]3 years ago
6 0

2. CD = CD , Reflexive Prop.

3. BC = DE, Subtraction Prop.

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The diagram shows a triangle.<br> 20s<br> 20s<br> 20s<br> What is the value of s?
Darina [25.2K]

Answer: I’m assuming that these are Angle measures. S=3

Step-by-step explanation:

180/3=60

20*3=60

S=3

3 0
3 years ago
Pls help ASAP need help pls
AlexFokin [52]

Answer:

1.625

Step-by-step explanation:

First we need to find the mean of this data set

29+32+33+28+30+30+29+33=244

Then we divide 244 by the amount of numbers in the set

244/8=30.5

Then we need to find the deviation of each number

29 | 32 | 33 | 28 | 30 | 30 | 29 | 33

1.5 | 1.5 | 2.5 | 2.5 | 0.5 | 0.5 | 1.5 | 2.5

Then we take the mean from this set of data

1.5+1.5+2.5+2.5+0.5+0.5+1.5+2.5=13

Then divide

13/8=1.625

I hope this helps :)

4 0
3 years ago
Read 2 more answers
Find the limit. Use l'Hospital's Rule if appropriate. If there is a more elementary method, consider using it.
grandymaker [24]
(2x+1)^{\cot x}=\exp\left(\ln(2x+1)^{\cot x}\right)=\exp\left(\cot x\ln(2x+1)\right)=\exp\left(\dfrac{\ln(2x+1)}{\tan x}\right)

where \exp(x)\equiv e^x.

By continuity of e^x, you have

\displaystyle\lim_{x\to0^+}\exp\left(\dfrac{\ln(2x+1)}{\tan x}\right)=\exp\left(\lim_{x\to0^+}\dfrac{\ln(2x+1)}{\tan x}\right)

As x\to0^+ in the numerator, you approach \ln1=0; in the denominator, you approach \tan0=0. So you have an indeterminate form \dfrac00. Provided the limit indeed exists, L'Hopital's rule can be used.

\displaystyle\exp\left(\lim_{x\to0^+}\dfrac{\ln(2x+1)}{\tan x}\right)=\exp\left(\lim_{x\to0^+}\dfrac{\frac2{2x+1}}{\sec^2x}\right)

Now the numerator approaches \dfrac21=2, while the denominator approaches \sec^20=1, suggesting the limit above is 2. This means

\displaystyle\lim_{x\to0^+}(2x+1)^{\cot x}=\exp(2)=e^2
7 0
3 years ago
Vertex = (2,5), Point (0, 1)
Rama09 [41]

Answer:

therefore y= - (x-2)^2 + 5

Step-by-step explanation:

u do this by using this format here ..,

y=a(x-h)^2+k

sub in the vertex points as h=2 and k = 5 , since the 2 is positive its sign will be -2 in the brackets because when solving for x-2=0 it is x=2

y=a(x-2)^2+5

then with your (0,1) points plug that in as y and x

1=a(0-2)^2+5

1=a(-2)^2+5

1=4a+5

1-5=4a

-4=4a

a=-1

therefore y= - (x-2)^2 + 5

8 0
2 years ago
I need to know the answer to the question in the picture
stiks02 [169]

Answer:

The correct answer is C. 3x(3x+1)

3 0
3 years ago
Read 2 more answers
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